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东北大学2024级计算机组成原理第二单元测试题.docx

1、东北高校2024级计算机组成原理其次单元测试题只能保证50+图片看不清就拉大了看哈=RS1Fora8-bitscomplementrepresentationintegernumber.的minimalVahleis127.itsmaximalvalueis127河引2The()representationof40,isunique.A.scomplement百B.2,scomplementC.signmagnitudeD.signmagnitudeandscomplement问舞3Therangeofrepresentationforascomplementnumbersystemof64b

2、its(includingthesignbit)is().aOWlNIW262-1BoWINlW263-1OCOWlNlW263DoWlNlW264-l河河48-4-2-1BCDcodeofanumberisOlll10001001,thenitstruevalueis789问题5WhenlX0,xsign-magnitude=()A.l-b(2-2-flxC.2+xD.问题6WhiChofthefollowingnumbersisoddparity?OA.110100111B.001000111C.110100111D.010110011问题72scomplementrepresentati

3、onof,0,equalstoTscomplementrepresentationof-.e对错问题8Theminimalnumberofthefollowingnumbersis().A(625)16B.(100101)2C.(100010)BCDD.(50)8河第9Adecimalnumberis137.5,dienitsoctalformis2114,itshexadecimalf11nis89.8:.河题10Therangeofrepresentationfora2,scomplementnumbersystemof16bits(includingthesignbit)is().您AA

4、215-+(215-l)。b-(215-l)+(215-l)Oc-(215+1)+215OD.215+215河善11In2scomplementadditionsubtraction,using2signbitsforoverflowdetection,whenthe2signbitsSSequalsfc10,.nmeansthat().A.resultisoverflowBresultisnegative,WithnooverflowOCresult:sunderflowDresultisposrthe.Wnhnooverflow问题12()isusedtorepresentaddres

5、sincomputer.A.signmagnitudeOB.2,scomplementQC.unsignednumberQD.scomplement问邕13Plustwo2,scomplementnumbersthatadopt1signbitoverflowmustoccurwhen().QA.XORoperationforcanysignalgeneratedfromthesignbitandCanysignalgeneratedfromthehighestnumencalbitisO)B.carrysignalISgeneratedfromthesignbitC.XORoperation

6、forca11signalgeneratedfromthesignbitandcarrysignalgeneratedfromthehighestnumericalbitisc0D.XORoperationforCanysignalgeneratedfromthesignbitandCarrysignalgeneratedfromthehighestnumencalbitis问题14IfPQ2*scomplement=0.1101010,thenXsign-magnitude=()A.1.0010101B.0.0010110C.1.0010110D.0.1101010问题15Fixedpoin

7、tnumbercanbeclassifiedintopuredecimal(纯小数)andpureinteger(纯整数).对。错间也16Therangeofrepresentationforaunsignedbinarynumbersystemof16bitsi$065535.问题17Theuseof2,scomplementoperationisadoptedtosimplifythedesignofcomputer.对错河Sg18Theadditionsubtractionalgorithmforsignmagnituderepresentationisrathersimple.对t错r

8、t192分AnthmebcshiftTicomplementofaPaSmVe,signbre11umsunchanged,andtheblkbtffi11m*0,Anthmeocleftshift2,sCompGevnentofanegamaelssgobtremanunchanged,ndthetowbitfiUs0Arithmeticrbtshift2sCofnPIememofanegative,signbitrenwnsunchanged.2ndthehighbstfills1.andtiUDcatkwbit.MS20IfpJ2SComPIement=1.1111,thenPsign-

9、magnitude=()A.0.0010110B1.0010101。C.1.0010110D.0.1101010HX21Fora8-brt2,scomplementrepresentationintegernumber,itsminimalvalueis-128.itsmaximalvalueis127诃题22FixedpointCalCUIatOrisusedfor().A.floatingpointoperationB.fixedpointoperation。C.decimaladditionD.fixedpointoperationandfloatingpointoperationNan

10、basXj.2arcinteger,and()2compi10011011.【X?】2cco(p三0001IOl1.thenthrtw%,alcofdecimalformarc-101and问题248-4-2-1codeisbinarymmber.对惜问题251.etthewordlengthis8thefixedpointintegerwith2,scomplementrepresentationof-1is11111111问题26Infixedpointcalculator,whetheradopteddoublesignbitorsinglesignbit.itmusthas().whi

11、chisoftenimplementedby().A.shiftcircuit.AND-ORgate0B.Decodingcircuit,NANDgate0Cencodingcircuit,NORgateoDoverflowdetectioncircuit,XORgateHS27Thenumberrepresentedinthecomputersometimeswillbeoverflow,thefundamentalreasonisthelimitedcomputerwordlength问题28Forfixedpointbinarycalculator,subtractionisimplem

12、entedthrough().与A.2,scomplementbinaryadderB.signmagnitudebinarysubtractorC.2scomplementbinarysubtractorD.signmagnitudedecimaladderHS292分GrvenlJ2*scornpltx2signmag=1011decimalvalueofand2are-52and-0375问题30The2scomplementrepresentationof-127is10000000.对修错问题31Afixedpointnumberiscomposedofsignbitandnumer

13、icalpart.对错问题32Themaximalnumberofthefollowingnumbersis().A.(10010101)2B.(143)5C(96)16D.(227)河引33Thesign-magnituderepresentationoft0,isunique.对e错问题34Infixedpointoperation,itwillbeoverflowwhentheresultexceedstherepresentrangeofthecomputer.对O错河题352:Forsignmagnituderepresentation_1$complementrepresenutn,2$complementrepresentation,sgnmgnituderepresent)and1$coml*mtftrepresenthas2reptcscmatioQsof*0

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