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1、e(IIItypeboundarycondition).精品文档InstructionofAnsystemperaturefieldcalculationQuestion1:Consideraninfinite(inonedirection)platewithinitialtemperatureT0.OneendoftheplateisexposedtotheenvironmentofwhichthetemperatureisTAnalyzethetemperaturedistributionintheplateduringtheperiodof2000s.问题1：考虑一个方向无限长的平板，初
2、始温度为T0，一段暴露在温度为Te的环境中，分析其在2000s内温度分布情况。Basicparameters基本物性参数Geometry几何：a=1m,b=0.1mMaterial材料：=54W/moC,=7800kg/m3,cp=465J/kgoCLoads载荷：T0=0oC,Te=1000oC,h=50W/m2oCJobnameanddirectorysettings设置文件名、存储路径Menu|File|ChangeJobnameMenu|File|ChangeDirectoryPreprocessing前处理(1)DefineElementType定义单元类型Preprocessor|
3、ElementType|Add/Edit/DeleteAdd:ThermalMass|Solid|Quad4node55(2)SetMaterialProperties设置材料属性Preprocessor|MaterialProps|MaterialModelsThermal:Conductivity:IsotropicKXX=54Thermal:Density=7800Thermal:SpecificHeat=465精品文档精品文档Modeling建模(1)CreateNode1建立节点1Preprocessor|Modeling|Create|Nodes|InActiveCSNo.:1,(
4、x,y,z)=(0,0,0)(2)CreateNode12建立节点12Preprocessor|Modeling|Create|Nodes|InActiveCSNo.:2,(x,y,z)=(0,1,0)(3)FillBetweenNode1and12在节点1，12间填充其余节点Preprocessor|Modeling|Create|Nodes|FillBetweenNdsNumberofnodestofill:10Spacingratio:1(均匀网格)(4)CreateNode1324bycopying复制生成节点1324Preprocessor|Modeling|Copy|Nodes|C
5、opyPickAll选择所有节点Totalnumberofcopies:2复制2份（包含原先的1份）X-offset:0.1设置X方向偏移量(5)CreateElement1生成单元1Preprocessor|Modeling|Create|Elements|AutoNumbered|ThruNodesSelect1,13,14,2(withmouse)(6)CopyElement210bycopying复制生成其余单元Preprocessor|Modeling|Copy|Elements|AutoNumberedPickAll选择所有单元Totalnumberofcopies:11复制11份
6、（包含原先的1份）Nodenumberincrement:1设置节点增量ApplyingLoads加载（设置边界条件和初始条件）(1)ApplyconventionloadsonNode12and24在节点12，24上加对流载荷Preprocessor|Loads|DefineLoads|Apply|Thermal|Convection|OnNodesPick12,24VALIFilmcoefficient:50换热系数VAL2LBulktemperature:1000环境温度(2)Setinitialtemperature(uniformtemperature)设置初始条件（均匀温度）Sol
7、ution|DefineLoads|Settings|UniformTempUniformTemperature:0Solution求解(1)SetAnalysisTypeasTransient设置分析类型为瞬态分析Solution|AnalysisType|NewAnalysisTransient精品文档精品文档设置n|Sol(2)Setsolutioncontrols分析控制参数Solution|AnalysisTypeControls”TransientLabel:SteppedLoading”Basic”Label:Timeatendofloadstep:10000;Automatic
8、timestepping:on;Timeincrement:0.ThetopFrequency:Writeeverysubstep(3)Solve求解Solution|Solve|CurrentLSViewingResults查看结果时(1)TimeHistPostpro间历程后处理器Adddata添加数据:TimeHistPostpro|Adddata:NodalSolution:DOFSolution:NodalTemperature:VariableName:T1;Node1VariableName:T5;Node5VariableName:T9;Node9VariableName:T1
9、1;Node11(2)List/Graph列表/作图选择Selectthevariables变量:Listdata/Graphdata(3)Saveimage保存图片Menu|PlotCtrls|CaptureImage:File|Saveas通(4)GeneralPostpro用后处理器选time:Selectthedataofcertain择某一时刻的数据GeneralPostpro|ReadResults|Bypick绘制该时:Plotthecontourmapoftemperaturedistribution刻温度分布等值线图GeneralPostpro|PlotResults|Con
10、tourPlot|NodalSolu|NodalSolution:DOFSolution:Temperature(5)Saveimage保存图片Menu|PlotCtrls|CaptureImage:File|Saveas(6)Animate生成动画Menu|PlotCtrls|Animate|OverTimeNumberofanimationframes:100TeisQuestion2:Considerasolidcylinderwithinitialtemperaturesurfaceofthecylinderisexposedtotheenvironmentofwhichthetemp
11、eratureT(IIItypeboundarycondition)andtheothersurfacesareheatinsulation(IItypeboundarycondition).Analyzethetemperaturedistributioninthecylinderduringtheperiodof1000s.问题2：考虑一个初始温度为T0的圆柱体，一段暴露在温度为Te的环境中，其余界面视为绝热，分析其在1000s内温度分布情况。精品文档精品文档Basicparameters基本物性参数Geometry几何：r=0.025m,h=0.05mMaterial材料：=25W/mo
12、C,=7800kg/m3,cp=500J/kgoCLoads载荷：T0=25oC,Te=100oC,h=100W/m2oCJobnameanddirectorysettings设置文件名、存储路径Menu|File|ChangeJobnameMenu|File|ChangeDirectoryPreprocessing前处理(1)DefineElementType定义单元类型Preprocessor|ElementType|Add/Edit/DeleteThermalMass:Solid:Brick8node70(2)SetMaterialProperties设置材料属性Preprocessor
13、|MaterialProps|MaterialModelsThermal:Conductivity:IsotropicKXX=25Thermal:Density=7800Thermal:SpecificHeat=500Modeling建模(1)Createthecylindermodel建立圆柱体模型Preprocessor|Modeling|Create|Volumes|Cylinder|SolidCylinderWPX:0WPY:0Radius:0.025Depth:0.05(2)Adjusttheview调整视图RightToolbar|IsometricView(3)Mesh划分网格P
14、reprocessor|Meshing|MeshToolSmartSize(optional):Mesh:selectthecylinder选择圆柱体精品文档精品文档ApplyingLoads加载(1)Applyconventionloadsonthetop在上表面加对流载荷Preprocessor|Loads|DefineLoads|Apply|Thermal|Convection|OnAreasPickthetopsurfacebymouse选择上表面(用鼠标)VALIFilmcoefficient:100换热系数VAL2LBulktemperature:100环境温度(2)Setinit
15、ialtemperature(uniformtemperature)设置初始条件（均匀温度）Solution|DefineLoads|Settings|UniformTempUniformTemperature:25Solution求解(1)SetAnalysisTypeasTransient设置分析类型为瞬态分析Solution|AnalysisType|NewAnalysisTransient(2)Setsolutioncontrols设置分析控制参数Solution|AnalysisType|SolnControls”Transient”Label:SteppedLoading”Basi
16、c”Label:Timeatendofloadstep:1000;Automatictimestepping:on;Timeincrement:10;Frequency:Writeeverysubstep(3)Solve求解Solution|Solve|CurrentLSViewingResults查看结果(1)GeneralPostpro通用后处理器:Selectthedataofcertaintime选择某一时刻的数据GeneralPostpro|ReadResults|Bypick:Plotthecontourmapoftemperaturedistribution绘制该时刻温度分布等值线图GeneralPostpro|PlotResults|ContourPlot|NodalSolu|NodalSolution:DOFSolution:Temperature(2)Saveimage保存图片Menu|PlotCtrls|CaptureImage:File|Saveas精品文档精品文档(3)Animate生成动画Menu|PlotCtrls|Animate|OverTimeNumberofanimationframes:100精品文档