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1、C实验报告答案 4 1 1 1c 2 3 4 5- 2 1if-else 2switch 3 1c- 1 2- 3 - 1 - 1 1main( ) /*/ char c1,c2; /*/ c1=97; c2=98; printf(%c %cn,c1,c2); /*/ printf(%d %dn,c1,c2); /*/ int c1c2 2main() int a=7,b=5; printf(%dn,b=b/a); printf%d%f 3main() int a=9; a+=a-=a+a; /*/ printf(%dn,a); aa-aa a=a-(a+a)=-9 a=a+a=18 4mai
2、n() int k=-1; printf(%d,%un,k,k); - 2 - -1 11111111111111111111111111111111(32) 5main() unsigned x1; int b=-1; x1=b; /*/ printf(%u,x1); 6main() int a=3,b=4,c=5; printf(%dn,(!(alt;b)amp;amp;(c=c+1); printf(%d,c); 16 7main() int a=1,b=2,c=3; if(c=a) ; printf(%dn,c); else printf(%dn,b); 2() 1 - 3 - 1)
3、switch 2) 3) 4) -10306068758395102 - 4 - 2 ?0.63%? ?0.66%? ?0.69% ?0.75%? ?0.84% ?1?2?3?5 ?8 12 - 5 - c5 5 - 1-3whiledowhilefor 2- 1 111005050sy5_1.c #include lt;stdio.hgt; main() int i,sum=0; i=1; while(ilt;100) while(ilt;=100) sum=sum+i; sum=sum+i; i+; i+; printf(the sum from 1 to 100 is %dn,sum);
4、 226sy5_2.c #include lt;stdio.hgt; main() char x; x=z; while(x!=a) while(x!=a-1)while(xgt;=a) printf(%3d,x); printf(%3c,x); x+; x- -; 3a sy5_3.cd #include lt;stdlib.hgt; main() int i,j,k; char ch; scanf(%c,amp;ch); k=ch-a+1; for (i=1;ilt;=k;i+) for (j=20;jgt;=i;j-) printf(%c, ); for (j=1;jlt;=i-1;j+
5、) for (j=1;jlt;=2*i-1;j+) printf(%c,a+i-1); printf(n); k=ch-a; for (i=k;igt;=1;i-) for (i=20;igt;=i;i-) for (j=20;jgt;=i;j-) printf(%c, ); for (j=1;jlt;2*i-1;j+) for (j=1;jlt;=2*i-1;j+) printf(%c,a+i-1); printf(n); 2 1sy5_4.c #include lt;stdio.hgt; main () scanf (%d%d,amp;m,amp;n); if (mlt;n) /*/ k=
6、m*n; r = m%n; while (r) m=n; n=r; ; printf (%d */ 21020sy5_5.c #include lt;stdio.hgt; main( ) int day,x1,x2; day=0; x1=1020; ; x1=x2; day+; printf(day=%dn,day); 310036.sy5_6.c #include lt;stdio.hgt; main() int i,j; for(i=0; _; i+) j=i*10+6; if (_) continue; printf(%d,j); 3 111008sy5_7.c #include lt;
7、stdio.hgt; main() int i, sum=0; for(i=1; ilt;=100; i+) if(i%10=8 | i/10=8) sum+=i; printf(sum=%dn,sum); 2e10-5sy5_8.c e?1?1111?-? 1!2!3!n! #include lt;stdio.hgt; main() int i=0 ; long n=1; float e=0, t=1; while(tgt;1e-5) e+=t; i+; n*=i; t=1.0/n; printf(e=%fn,e); 3527331sy5_9.c #include lt;stdio.hgt;
8、 main() int i; for(i=900;ilt;=1000;i+) if(i%5=2amp;amp;i%7=3amp;amp;i%3=1) break; printf(=%dn,i); 4nmsy5_10.c #includelt;stdio.hgt; void main() int i,j,n,m,no,score,sum; float ave; printf( ); scanf(%d%d,amp;n,amp;m); for(i=1;ilt;=n;i+) sum=0; printf(%d: ,i); scanf(%d,amp;no); printf(%d%d: ,i,m); for(j=1;jlt;=m;j+) scanf(%d,amp;score); sum+=score; ave=(float)sum/m; printf(n*%d %.2fnn,i,no,sum,ave); :%d %d c6 6 1 2 3 1 1sy6_1.c #includelt;stdio.hgt; void main() int n=10,i,sum=0; int an; int a10; for(i=0;ilt;10;i+) scanf(%d,ai); scanf(%d,amp;ai); sum=sum+ai; printf(sum=%dn,sum); .