《最新四川省广元市苍溪中学-高二数学上学期入学试卷+文含解析优秀名师资料.doc》由会员分享，可在线阅读，更多相关《最新四川省广元市苍溪中学-高二数学上学期入学试卷+文含解析优秀名师资料.doc（40页珍藏版）》请在三一文库上搜索。
1、四川省广元市苍溪中学2014-2015学年高二数学上学期入学试卷 文(含解析)四川省广元市苍溪中学2014-2015学年高二上学期入学数学试卷 (文科) 一、选择题(本大题共10个小题，每小题5分，共50分) 21(5分)化简:(sin+cos)=() A( 1+sin2 B( 1,sin C( 1,sin2 D( 1+sin 2(5分)在?ABC中，若a=2，A=30?则B为() A( 60? B( 60?或120? C( 30? D( 30?或150? 3(5分)在数列1，1，2，3，5，8，x，21，34，55中，x等于() A( 11 B( 12 C( 13 D( 14 4(5分)如图
2、是一个几何体的三视图，则该几何体为() A( 球 B( 圆柱 C( 圆台 D( 圆锥 5(5分)一个长方体相邻的三个面的面积分别是2，3，6，这个长方体的顶点都在同一个球面上，则这个球的表面积为() A( B( 14 C( 56 D( 64 6(5分)设数列a和b都是等差数列，其中a=70，b=30，且a+b=100，则数列a+bnn11100100nn的前100项之和是() A( 1000 B( 1100 C( 10000 D( 11000 7(5分)已知等比数列a的公比q=,，则等于() nA( , B( ,3 C( D( 3 8(5分)设a,b，c,d，则下列不等式恒成立的是() A(
3、a,c,b,d B( ac,bd C( D( b+d,a+c of leadership, along with 500-1000 punishment. (5) significant near miss should be attempted as the case of responsible for the accident and construction team injuries accident penalty provisions, mutatis mutandis. Eight, should perform in the construction standards an
4、d specifications, serial number a 1 GB3323-2005 steel fusion welded butt joints, welding engineering-Ray lighting and quality rating of 2 GB11345-89 steel welds manual methods of ultrasonic inspection and testing results for grade 3 GB50236-2002 industrial pipe welding engineering code for construct
5、ion and acceptance of field equipment 4 HGJ222-92 technical specification for welding of aluminium and its alloys 5 low temperature steel welding procedure 6 SH3525-2004 petrochemical JB/ T4708-2000 of welding procedure qualification for steel pressure vessels 7 JB/4709-2000 8 JB4730-2005 pressure v
6、essel welding procedures of steel pressure vessel NDT 9 JB/T4744-2000 steel pressure vessel products mechanical properties test of welded plate II, mechanical equipment installation engineering 1 GB150-98 2 GB50128-2005 vertical cylindrical steel pressure vessel steel welded specification for constr
7、uction and acceptance of oil tank 3 JB/ T4735-1997 steel welded atmospheric pressure vessel 4 GB50231-2009 mechanical equipment installation engineering construction and acceptance specification for 5 GB50275-98 compressor, fan and pump installation engineering construction and acceptance specificat
8、ion for lifting 6 HG20201-2000 construction installation engineering construction standard 7, HG . Pressure gauges, using an installed spark arrestor for acetylene cylinders, illegal carrying, using gas cylinders, each operator fined 20 Yuan. Gas bottle without the hot 229(5分)如果方程x+(m,1)x+m,2=0的两个实根
9、一个小于1，另一个大于1，那么实数m的取值范围是() A( B( (,2，0) C( (,2，1) D( (0，1) *10(5分)已知数列a满足a=0，a=(n?N)，则a=() n1n+120A( 0 B( C( D( 二、填空题(本大题共5个小题，每小题5分，共25分) 11(5分)在?ABC中，若a=3，cosA=,，则?ABC的外接圆的半径为( 12(5分)将27个边长为a的小正方体拼成一个大正方体，则表面积减少了( 13(5分)等差数列a的前m项和为30，前3m项和为210，则它的前2m项和是( n14(5分)已知等比数列a中，a+a=9，aaa=27，则a的前n项和S=( n12
10、123nn215(5分)不等式ax+bx+2,0的解集为(,，)，则a+b等于( 三、简答题(本大题共6小题，共75分，简答题应写出文字说明、证明过程或演算步骤) 16(12分)在?ABC中，,B,，AB=，BC=3，sinC=( (1)求sinA的值; (2)求?ABC的面积( 17(12分)如图，四边形ABCD是边长为1的正方形，MD?平面ABCD，NB?平面ABCD，且MD=NB=1， (?)以向量方向为侧视方向，侧视图是什么形状,说明理由并画出侧视图( (?)求该几何体的体积( 92 technical specification for welding of aluminium an
11、d its alloys 5 low temperature-2002 industrial pipe welding engineering code for construction and acceptance of field equipment 4 HGJ222-of ultrasonic inspection and testing results for grade 3 GB50236 89 steel welds manual methods-Ray lighting and quality rating of 2 GB11345-2005 steel fusion welde
12、d butt joints, welding engineering-visions, mutatis mutandis. Eight, should perform in the construction standards and specifications, serial number a 1 GB3323n team injuries accident penalty pro1000 punishment. (5) significant near miss should be attempted as the case of responsible for the accident
13、 and constructio-of leadership, along with 500-without the hot for acetylene cylinders, illegal carrying, using gas cylinders, each operator fined 20 Yuan. Gas bottle 2000 construction installation engineering construction standard 7, HG . Pressure gauges, using an installed spark arrestor-tion for
14、lifting 6 HG2020198 compressor, fan and pump installation engineering construction and acceptance specifica-2009 mechanical equipment installation engineering construction and acceptance specification for 5 GB50275-1997 steel welded atmospheric pressure vessel 4 GB50231-35T472005 vertical cylindrica
15、l steel pressure vessel steel welded specification for construction and acceptance of oil tank 3 JB/ -98 2 GB50128-ssel products mechanical properties test of welded plate II, mechanical equipment installation engineering 1 GB1502000 steel pressure ve-2005 pressure vessel welding procedures of steel
16、 pressure vessel NDT 9 JB/T4744-2000 8 JB4730-2000 of welding procedure qualification for steel pressure vessels 7 JB/4709-2004 petrochemical JB/ T4708-steel welding procedure 6 SH3525 2 - 文档来源:弘毅教育园丁网数学第一站 18(12分)如图，在三棱锥P,ABC中，PC?底面ABC，AB?BC，D，E分别是AB、PB的中点( (1)求证:DE?平面PAC; (2)求证:AB?PB( 19(12分)在等差数列
17、a中，已知a=2，a=4( n24(1)求数列a的通项公式a; nn(2)设b=，求数列b前5项的和S( nn520(13分)如图，某动物园要建造两间完全相同的矩形熊猫居室，其总面积为24平方米，设熊猫居室的一面墙AD的长为x米 (2?x?6)( (1)用x表示墙AB的长; (2)假设所建熊猫居室的墙壁造价(在墙壁高度一定的前提下)为每米1000元，请将墙壁的总造价y(元)表示为x(米)的函数; (3)当x为何值时，墙壁的总造价最低, n+1n*21(14分)已知数列a满足:a=2，a=3a+3,2(n?N) n1n+1n(1)设b=，证明:数列b为等差数列，并求数列a的通项公式; nnn(2
18、)求数列a的前n项和S; nn*(3)设C=(n?N)，是否存在k?N，使得C?C对一切正整数n均成立，并说明理由( nnk四川省广元市苍溪中学2014-2015学年高二上学期入学数学试卷(文科) 参考答案与试题解析 -results for grade 3 GB50236 89 steel welds manual methods of ultrasonic inspection and testing-Ray lighting and quality rating of 2 GB11345-2005 steel fusion welded butt joints, welding engi
19、neering-uld perform in the construction standards and specifications, serial number a 1 GB3323n team injuries accident penalty provisions, mutatis mutandis. Eight, sho1000 punishment. (5) significant near miss should be attempted as the case of responsible for the accident and constructio-of leaders
20、hip, along with 500-lene cylinders, illegal carrying, using gas cylinders, each operator fined 20 Yuan. Gas bottle without the hotruction installation engineering construction standard 7, HG . Pressure gauges, using an installed spark arrestor for acety2000 const-98 compressor, fan and pump installa
21、tion engineering construction and acceptance specification for lifting 6 HG20201-2009 mechanical equipment installation engineering construction and acceptance specification for 5 GB50275-sure vessel 4 GB502311997 steel welded atmospheric pres-T47352005 vertical cylindrical steel pressure vessel ste
22、el welded specification for construction and acceptance of oil tank 3 JB/ -98 2 GB50128-est of welded plate II, mechanical equipment installation engineering 1 GB1502000 steel pressure vessel products mechanical properties t-2005 pressure vessel welding procedures of steel pressure vessel NDT 9 JB/T
23、4744-2000 8 JB4730-2000 of welding procedure qualification for steel pressure vessels 7 JB/4709-4 petrochemical JB/ T4708200-92 technical specification for welding of aluminium and its alloys 5 low temperature steel welding procedure 6 SH3525-2002 industrial pipe welding engineering code for constru
24、ction and acceptance of field equipment 4 HGJ222 3 - 一、选择题(本大题共10个小题，每小题5分，共50分) 21(5分)化简:(sin+cos)=() A( 1+sin2 B( 1,sin C( 1,sin2 D( 1+sin 考点: 二倍角的正弦;同角三角函数基本关系的运用( 专题: 三角函数的求值( 2 分析: 把(sin+cos)展开，利用同角三角函数的基本关系、二倍角的正弦公式可求得结果( 2 解答: 解:?(sin+cos)=1+2sincos=1+sin2， 故选:A( 点评: 本题主要考查二倍角的正弦公式的应用，属于基础题(
25、2(5分)在?ABC中，若a=2，A=30?则B为() A( 60? B( 60?或120? C( 30? D( 30?或150? 考点: 正弦定理( 专题: 计算题( 分析: 利用正弦定理和题设中两边和一个角的值求得B( 解答: 解:由正弦定理可知 =， ?sinB= ?B?(0，180?) ?B=60?或120? 故选B( 点评: 本题主要考查了正弦定理的应用(正弦定理常用来运用a:b:c=sinA:sinB:sinC解决角之间的转换关系(属于基础题( 3(5分)在数列1，1，2，3，5，8，x，21，34，55中，x等于() A( 11 B( 12 C( 13 D( 14 考点: 数列的
26、概念及简单表示法( 专题: 计算题( 分析: 从已知数列观察出特点:从第三项开始每一项是前两项的和即可求解 解答: 解:?数列1，1，2，3，5，8，x，21，34，55 设数列为a n?a=a+a (n,3) nn,1n,2?x=a=a+a=5+8=13 756故选C 点评: 本题考查了数列的概念及简单表示法，是斐波那契数列，属于基础题( 4(5分)如图是一个几何体的三视图，则该几何体为() -steel welding procedure 6 SH3525 92 technical specification for welding of aluminium and its alloys
27、5 low temperature-2002 industrial pipe welding engineering code for construction and acceptance of field equipment 4 HGJ222-of ultrasonic inspection and testing results for grade 3 GB50236 89 steel welds manual methods-Ray lighting and quality rating of 2 GB11345-2005 steel fusion welded butt joints
28、, welding engineering-visions, mutatis mutandis. Eight, should perform in the construction standards and specifications, serial number a 1 GB3323n team injuries accident penalty pro1000 punishment. (5) significant near miss should be attempted as the case of responsible for the accident and construc
29、tio-of leadership, along with 500-without the hot for acetylene cylinders, illegal carrying, using gas cylinders, each operator fined 20 Yuan. Gas bottle 2000 construction installation engineering construction standard 7, HG . Pressure gauges, using an installed spark arrestor-tion for lifting 6 HG2
30、020198 compressor, fan and pump installation engineering construction and acceptance specifica-2009 mechanical equipment installation engineering construction and acceptance specification for 5 GB50275-1997 steel welded atmospheric pressure vessel 4 GB50231-35T472005 vertical cylindrical steel press
31、ure vessel steel welded specification for construction and acceptance of oil tank 3 JB/ -98 2 GB50128-ssel products mechanical properties test of welded plate II, mechanical equipment installation engineering 1 GB1502000 steel pressure ve-2005 pressure vessel welding procedures of steel pressure ves
32、sel NDT 9 JB/T4744-2000 8 JB4730-2000 of welding procedure qualification for steel pressure vessels 7 JB/4709-2004 petrochemical JB/ T4708 4 - 文档来源:弘毅教育园丁网数学第一站 A( 球 B( 圆柱 C( 圆台 D( 圆锥 考点: 由三视图求面积、体积( 专题: 探究型( 分析: 由三视图可知该几何体为圆锥( 解答: 解:根据三视图可知，该几何体为圆锥( 故选D( 点评: 本题主要考查三视图的识别和判断，比较基础( 5(5分)一个长方体相邻的三个面的面
33、积分别是2，3，6，这个长方体的顶点都在同一个球面上，则这个球的表面积为() B( 14 C( 56 D( 64 A( 考点: 球的体积和表面积( 专题: 计算题( 分析: 由题意长方体的外接球的直径就是长方体的对角线，求出长方体的对角线，就是求出球的直径，然后求出球的表面积( 解答: 解:因为一个长方体相邻的三个面的面积分别是2，3，6， ?长方体的一个顶点上的三条棱长分别是3，2，1，且它的8个顶点都在同一个球面上， 所以长方体的对角线就是确定直径， 长方体的体对角线的长是: 球的半径是: 这个球的表面积:4 =14 200-92 technical specification for w
34、elding of aluminium and its alloys 5 low temperature steel welding procedure 6 SH3525-2002 industrial pipe welding engineering code for construction and acceptance of field equipment 4 HGJ222-results for grade 3 GB50236 89 steel welds manual methods of ultrasonic inspection and testing-Ray lighting
35、and quality rating of 2 GB11345-2005 steel fusion welded butt joints, welding engineering-uld perform in the construction standards and specifications, serial number a 1 GB3323n team injuries accident penalty provisions, mutatis mutandis. Eight, sho1000 punishment. (5) significant near miss should b
36、e attempted as the case of responsible for the accident and constructio-of leadership, along with 500-lene cylinders, illegal carrying, using gas cylinders, each operator fined 20 Yuan. Gas bottle without the hotruction installation engineering construction standard 7, HG . Pressure gauges, using an
37、 installed spark arrestor for acety2000 const-98 compressor, fan and pump installation engineering construction and acceptance specification for lifting 6 HG20201-2009 mechanical equipment installation engineering construction and acceptance specification for 5 GB50275-sure vessel 4 GB502311997 stee
38、l welded atmospheric pres-T47352005 vertical cylindrical steel pressure vessel steel welded specification for construction and acceptance of oil tank 3 JB/ -98 2 GB50128-est of welded plate II, mechanical equipment installation engineering 1 GB1502000 steel pressure vessel products mechanical proper
39、ties t-2005 pressure vessel welding procedures of steel pressure vessel NDT 9 JB/T4744-2000 8 JB4730-2000 of welding procedure qualification for steel pressure vessels 7 JB/4709-4 petrochemical JB/ T4708 5 - 故选B( 点评: 本题是基础题，考查球的内接多面体的有关知识，球的表面积的求法，注意球的直径与长方体的对角线的转化是本题的解答的关键，考查计算能力，空间想象能力( 6(5分)设数列a和
40、b都是等差数列，其中a=70，b=30，且a+b=100，则数列a+bnn11100100nn的前100项之和是() A( 1000 B( 1100 C( 10000 D( 11000 考点: 等差数列的性质( 专题: 等差数列与等比数列( 分析: 由数列a和b都是等差数列，得到数列a+b也是等差数列，然后利用已知直接nnnn由等差数列的前n项和得答案( 解答: 解:?a、b都是等差数列， nn?a+b是等差数列， nn?a=25，b=75，a+b=100， 11100100?a+b+a+b=200， 11100100?S=10000( 100故选:C( 点评: 本题考查了等差数列的通项公式，
41、考查了等差数列的性质，是基础题( 7(5分)已知等比数列a的公比q=,，则等于() nA( , B( ,3 C( D( 3 考点: 等比数列的性质( 专题: 计算题( 分析: 根据=，进而可知=，答案可得( 解答: 解:?=， ?=,3( 故选B 点评: 本题主要考查了等比数列的性质(属基础题( 8(5分)设a,b，c,d，则下列不等式恒成立的是() -2002 industrial pipe welding engineering code for construction and acceptance of field equipment 4 HGJ222-of ultrasonic in
42、spection and testing results for grade 3 GB50236 89 steel welds manual methods-Ray lighting and quality rating of 2 GB11345-2005 steel fusion welded butt joints, welding engineering-visions, mutatis mutandis. Eight, should perform in the construction standards and specifications, serial number a 1 G
43、B3323n team injuries accident penalty pro1000 punishment. (5) significant near miss should be attempted as the case of responsible for the accident and constructio-of leadership, along with 500-without the hot for acetylene cylinders, illegal carrying, using gas cylinders, each operator fined 20 Yua
44、n. Gas bottle 2000 construction installation engineering construction standard 7, HG . Pressure gauges, using an installed spark arrestor-tion for lifting 6 HG2020198 compressor, fan and pump installation engineering construction and acceptance specifica-2009 mechanical equipment installation engine
45、ering construction and acceptance specification for 5 GB50275-1997 steel welded atmospheric pressure vessel 4 GB50231-35T472005 vertical cylindrical steel pressure vessel steel welded specification for construction and acceptance of oil tank 3 JB/ -98 2 GB50128-ssel products mechanical properties te
46、st of welded plate II, mechanical equipment installation engineering 1 GB1502000 steel pressure ve-2005 pressure vessel welding procedures of steel pressure vessel NDT 9 JB/T4744-2000 8 JB4730-2000 of welding procedure qualification for steel pressure vessels 7 JB/4709-2004 petrochemical JB/ T4708-s
47、teel welding procedure 6 SH3525 92 technical specification for welding of aluminium and its alloys 5 low temperature 6 - 文档来源:弘毅教育园丁网数学第一站 A( a,c,b,d B( ac,bd C( D( b+d,a+c 考点: 不等关系与不等式( 专题: 计算题( 分析: 本题是选择题，可采用逐一检验，利用特殊值法进行检验，很快问题得以解决( 解答: 解:?a,b，c,d ?设a=1，b=,1，c=,2，d=,5 选项A，1,(,2),1,(,5)，不成立 选项B，1(
48、,2),(,1)(,5)，不成立 取选项C，不成立 故选D 点评: 本题主要考查了基本不等式，基本不等式在考纲中是C级要求，本题属于基础题( 229(5分)如果方程x+(m,1)x+m,2=0的两个实根一个小于1，另一个大于1，那么实数m的取值范围是() A( B( (,2，0) C( (,2，1) D( (0，1) 考点: 一元二次方程的根的分布与系数的关系( 专题: 计算题( 2222分析: 构造函数f(x)=x+(m,1)x+m,2，根据方程x+(m,1)x+m,2=0的两个实根一个小于1，另一个大于1，可得f(1),0，从而可求实数m的取值范围( 22解答: 解:构造函数f(x)=x+(m,1)x+m,2， 22?方程x+(m,1)x+m,2=0的两个实根一个小于1，另一个大于1， ?f(1)