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1、程序设计技术（第三版）习题参考答案习题1一、单项选择题DADDDB CCD（注：第7小题无正确选项，正确答案为-12）二、填空题 主 main x=x*(x+b) 普通、格式、分隔和转义 指定输出数据格式 void main() how are you! 三、阅读程序题1.9,11,9,10 2.2,-1,-13.aa bb cc abc4.2,25.57 5 767.5864000,-789.12402367.5864000, -7.89e+002 67,86, -789.12,67.5864000, -789.124023, 67.5864000, -789.1240236.758640e
2、+001, -7.89e+002A,65,101,411234567,4553207,12d68765535,177777,ffff,65535COMPUTER, COM.6. a + c = 102a + c = ff + m = 17.950000a + m = 17.650000c + f = 102.300000double = 1746.150019四、程序设计题/xt010401.cpp#include #define PI 3.1415926void main()double r,h;printf(请输入半径r和高h：);scanf(%lf,%lf,&r,&h);printf(圆
3、半径: %lfn,2*PI*r);printf(圆面积：%lfn,PI*r*r);printf(圆球表面积：%lfn,4*PI*r*r);printf(圆球体积：%lfn,4.0/3*PI*r*r);printf(圆柱体积：%lfn,PI*r*r*h);/xt010402.cpp#include void main()int c;printf(Input a character:);c=getchar();printf(%ct%dn,c,c);/xt010403.cpp#include void main()int x,y,h=30,f=90;x=(4*h-f)/2;y=(f-2*h)/2;p
4、rintf(鸡：%d, 兔：%dn,x,y);/xt010404.cpp#include #include void main()double a,b,c,s,area;printf(请输入三角形的三条边长（注意三条边长应能够构成三角形）：);scanf(%lf,%lf,%lf,&a,&b,&c);s=(a+b+c)/2;area=sqrt(s*(s-a)*(s-b)*(s-c);printf(三角形的面积是: %lfn,area);/xt010405.cpp#include void main()double f,c;printf(请输入华氏温度：);scanf(%lf,&f);c=5.0/
5、9.0*(f-32);printf(与华氏温度%.2lf对应的摄氏温度是：%.2lfn,f,c);/xt010406.cpp#include void main()char c1,c2,c3,c4,c5;printf(请输入需加密的字符串（5个字符）：);c1=getchar();c2=getchar();c3=getchar();c4=getchar();c5=getchar();printf(加密后的字符串是：);putchar(c1+5);putchar(c2+5);putchar(c3+5);putchar(c4+5);putchar(c5+5);printf(n);习题2一、 单项选
6、择题CBADC CCAAC二、填空题 a+b=0&a*b!=0 逻辑与 逻辑或 continue (c= getchar ()!=n %c三、阅读程序题答案：答案：该程序所完成功能的函数关系为：答案： 答案： 答案： 答案： 四、程序设计题/* xt020401.cpp */#include void main()int num; printf(* Input num: *n); scanf(%d,&num); if(num%3=0&num%5=0&num%7=0) printf(* YES ! *n); else printf(* NO ! *n);/* xt020402.cpp */#in
7、clude void main()int h=0;float x,y,x0=2,y0=2,d1,d2,d3,d4;printf(* input: x,y *n);scanf(%f,%f,&x,&y); d1=(x-x0)*(x-x0)+(y-y0)*(y-y0); /*点（x,y）到各中心点的距离*/ d2=(x-x0)*(x-x0)+(y+y0)*(y+y0); d3=(x+x0)*(x+x0)+(y-y0)*(y-y0); d4=(x+x0)*(x+x0)+(y+y0)*(y+y0); if(d1=1|d2=1|d3=1|d4=1) h=15; printf(x=%f, y=%fn,x,y
8、); printf(h=%dn,h);/* xt020403.cpp */#include void main() int i,j,k,n; for(n=100;n=999;n+)i=n/100; j=n/10-i*10; k=n%10; if(n=i*i*i+j*j*j+k*k*k)printf(%dn,n); /* xt020404.cpp */#include #include #define EPS 1.0e-6void main() float e=1,t; long int j=1,n=1; do j=j*n; t=1.0/j; e=e+t; n+; while ( fabs(t)
9、 = EPS ); printf(e=%fn,e); /* xt020405.cpp */#include void main()int num=1; do if(num+3)%5=0&(num-3)%6=0) break; num+=1; while(1);printf(num=%dn,num);/* xt020406.cpp */#include void main() int num; for(num=1;num=99;num+) if(num*num%10=num|num*num%100=num) printf(%4d,%5d,num,num*num); printf(n);/* xt
10、020407.cpp */#include void main() int n,k=1; float s=0; for(n=1;n=10000;n+) s=s+1.0/(2.0*n-1)*k; k=-k; printf(PI=%fn,4*s);/* xt020408.cpp */#include void main() int n10,n5,n2,n1; for(n10=1;n10=9;n10+) for(n5=1;n5=17;n5+) for(n2=1;n2=1&n10*10+n5*5+n2*2+n1=100) printf(n10=%d,n5=%d,n2=%d,n1=%dn,n10,n5,
11、n2,n1); /* xt020409.cpp */#include void main()float sn=100,hn=sn/2; int n=2; while(n=10) sn+=2*hn; hn=hn/2; n+; printf(%f,%fn,sn,hn);/* xt020410.cpp */#include void main() int day,x1,x2=1; for(day=9;day0;day-) x1=(x2+1)*2; x2=x1; printf(Total=%dn,x1);习题3单项选择题BBCAC DDABB填空题 9 0 10 x 一致 n/2 sum+a sum/
12、n三、阅读程序题1. 2 4 62. s=303. 5 9 45 8 424. lanuge5. 8 1 6 3 5 7 4 9 26. max=10,row=2,colum=1四、程序设计题/xt030401.cpp#include #include #include void main(void) int num10, a; srand(unsigned)time(NULL); printf(请输入一个2位数，试试您是否能中奖：); scanf(%d,&a); for(int i=0;i10;i+) numi = (rand()+10)%100; if(a = numi) printf(猜
13、中一个数 %d 下标是 %d,a,i); printf(-n); for( i=0; i10; i+) printf(%dt ,numi);/xt030402.cpp#include #include #include void main(void) int a5=23,45,60,67,88,x,i,j,yes=0; for(i=0;i5;i+) printf(%d,ai); printf(nwhich number do you want to delete?n); scanf(%d,&x); for(i=0;i5;i+) if(ai=x) yes=1; for(j=i;j5;j+) aj
14、=aj+1; if(yes=1) for(i=0;i4;i+) printf(%d,ai); else printf(The number you want doesnt exist); /xt030403.cpp#include #include #include #define SIZE 1000void main() int x,aSIZE,size,sum=0; srand(unsigned)time(NULL); while(size=rand()%1000)200); printf(nRandomiz list size(1000):%d,size); printf(nAuto m
15、ake a %d size of list:n,size); for(x=0;xsize;x+) ax=rand()%1000 ; printf(%dt,ax); sum+=arrx; printf(nThe sum of array elements is %d, sum);/xt030404.cpp#include #include #include #define SIZE 100void main() int x,aSIZE,max=0,min=1000,b1,b2;srand(unsigned)time(NULL); printf(nAuto make a %d size of li
16、st:n,size); for(x=0;xSIZE;x+) ax=rand()%1000 ; printf(%dt,ax); for(x=0;xmax) max=ax,b1=x; if(axmin) min=ax,b2=x; printf(nThe array elements max= %d in %d n min=%d in %dn,max,b1,min,b2);/xt030405.cpp#include #define SIZE 100#define KIND 5void main() int x,y,len,totalKIND+1; int a=1,1,1,1,2,2,2,3,5,5,
17、5,5,1,1,3,3,3,3,3,2,2,2,5,5,5; len=sizeof(a)/sizeof(a0); for(x=0;xKIND+1;x+) totalx=0 ; for(y=1;yKIND+1;y+) for(x=0;xlen;x+) if (ax=y) totaly+; printf(nThe list kinded:n); for(x=0;xlen;x+) printf( %d ,ax); printf(nThe total result: ); for(x=1;xKIND+1;x+) printf( %d-%d, ,x,totalx);/xt030406.cpp#defin
18、e N 26#include int main(void) static int aN+1,bN+1; int i,j,s,m,p; scanf(%d%d,&s,&m); for (i=1;i=N;i+) ai=i; i=s-1;j=0;p=0; while (pN) i-=N; if (ai=0) i+;goto bh; j+; if (j%m=0) p+;bp=ai;ai=0;j=0; for (i=1;i=N;i+) printf(%3d,bi); printf(n);/xt030407.cpp#include voidmain()inti,j,s=0,ave,v3;staticinta
19、53=80,75,92,61,65,71,59,63,70,85,87,90,76,77,85;for(i=0;i3;i+) for(j=0;j5;j+) s=s+aji; vi=s/5; s=0;ave=(v0+v1+v2)/3;printf(math:%dnclanguag:%dndbase:%dn,v0,v1,v2);printf(total ave:%dn,avel);/xt030408.cpp#include void main() int i,j,a1010, b=1,2,3,4,5,6,7,8,9,10; for(i=0;i10;i+) a0i=bi; for(i=1;i10;i
20、+) for(j=0;jj) aij=aji;else aij=ai-1j-1;for(i=0;i10;i+) for(j=0;j10;j+) printf(%dt,aij); printf(n); /xt030409.cpp#include #include #include #define SIZE 5000#define N 7void main() int x,y,aN=0,0,0,0,0,0,0,s;srand(unsigned)time(NULL); x=0; while(x0&s7) as+; x+; printf(nRandomiz 1-6 list n); for(x=1;x
21、N;x+) s=ax*0.07; for(y=0;ys;y+)printf(%d,x);printf(t%dt%2.1f%n,ax,(float)ax*100/SIZE); /xt030410.cpp#include #define N 20int main() int x,s,tag; char aN; printf(Please input numbers and its length less then %d:,N-1); s=1; while(sN) scanf(%c,&as); if(as=10)break; s+; printf(nThe numbers is :n); for(x
22、=1;xs;x+) printf(%c,ax); tag=0; for(x=1;xs/2;x+) if(ax!=as-x) tag=1; break; if(tag=0)printf(nThe number is palindrome!); else printf(nThe number isnt palindrome!);习题4一、 单项选择题ABACA BCBDD二、 填空题 主 main函数 main函数 个数 类型 顺序 函数类型 float(float x,int n) f(x,n) x*f(x,n-1) 三、阅读程序题1 x=5,y=252. y=170.03. s1=3.14,s
23、2=5.14 4. 5002 5. 5,3 6. 3.00,1.00,0.25四、程序设计题/xt040401.cpp #include void main( ) void dis(int n);int n;scanf(%d,&n);dis(n); void dis(int n) int k0,k,sum,i;k0=1;dok=k0;sum=0;for(i=1;i=n;i+)sum=sum+k;k=k+2;if(sum=n*n*n)break;elsek0=k0+2;while(1);for(i=1;i=n;i+)printf(%5d,k0);k0=k0+2;/xt040402.cpp#inc
24、lude void main( )float h(int n,float x);int n;float x;scanf(%d,%f,&n,&x);printf(h(%d,%f)=%f,n,x,h(n,x);float h(int n,float x)if(n=0)return 1;else if(n=1)return(2*x);elsereturn(2*x*h(n-1,x)-2*(n-1)*h(n-2,x);/xt040403.cpp#include void main()int f(int n);int i;for(i=2;i=1000;i+)if(f(i)printf(%6d,i);int
25、 f(int n)if(n=n*n%10|n=n*n%100|n=n*n%1000)return 1;elsereturn 0;/xt040404.cpp#include void main( )long fun(int a,int n);int k,n;scanf(%d,%d,&k,&n);printf(%ldn,fun(k,n);long fun(int a, int n)int j;long s=0,t=0;for(j=1;j=n;j+)t=t*10+a;s=s+t;return s;/xt040405.cpp#include #include void main()int num,mi
26、ddle1,middle2;int detect(int d);printf(Please input a positive even number(=6):);scanf(%d,&num);for(middle1=2;middle1=num/2;middle1+=1)if(detect(middle1)middle2=num-middle1;if(detect(middle2)printf(%d=%d+%dn,num,middle1,middle2);break;int detect(int d)int i;for(i=2;i=sqrt(d*1.0);i+)if(d%i=0)return(0
27、);return 1;/xt040406.cpp#include void main()float f(float x,int n);float x,an;int n;scanf(%f,%d,&x,&n);an=f(x,n);printf(an=%fn,an);float f(float x,int n)if(n=0)return 1;elsereturn x/n*f(x,n-1);/xt040407.cpp#include void main()float f(float x,int n);float x,fn;int n;scanf(%f,%d,&x,&n);fn=f(x,n);print
28、f(an=%fn,fn);float f(float x,int n)if(n=0)return 1;else if(n0)return x*f(x,n-1);elsereturn f(x,n+1)/x;/xt040408.cpp#include void main( )void f(int n);int n; scanf(%d,&n);while(n=0)scanf(%d,&n);f(n);void f(int n)if(n/10=0)putchar(n%10+0);elseputchar(n%10+0);f(n/10);/xt040409.cpp#include void main( )v
29、oid f(int n);int n; scanf(%d,&n);while(n=0)scanf(%d,&n);f(n);void f(int n)if(n/10)f(n/10);putchar(n%10+0); /xt040410.cpp#include void main()int f(int n);int n;for(n=2;n=1000;n+)if(f(n)printf(%d is a 完数n,n);int f(int n)int i,s=0;for(i=1;in;i+)if(n%i=0)s=s+i;if(s=n)return 1;elsereturn 0;习题5一、单项选择题AACC
30、A DDACB二、填空题 “char *func1()”定义一个返回字符指针值的函数，“char(*func2)()”定义一个指向函数的指针 一个返回值为单精度类型指针的函数名； (*p)(a,b,c) findmin (*f)(x,y,z); 三、阅读程序题112025,4,3344155112649111131315/xt050401.cpp#include stdio.hvoid main()void f(int,int,int);int a,b,c;void (*p)(int,int,int);scanf(%d%d%d,&a,&b,&c); p=f;(*p)(a,b,c); void
31、f(int x,int y,int z) int t;if(xy)t=x,x=y,y=t;if(yz)t=z,z=y,y=t;if(xy)t=x,x=y,y=t; printf(%5d%5d%5dn,x,y,z);/xt050402.cpp#include int max(int a,int b)if(ab)return a;else return b;void main()int max(int a,int b);int(*pmax)(int,int);int x,y,z;pmax=max;printf(input two numbers:n);scanf(%d%d,&x,&y);z=(*p
32、max)(x,y);printf(maxmum=%d,z);/xt050403.cpp#include stdio.hvoid gcd(int x,int y)int temp;while(y!=0)temp=x%y;x=y;y=temp;printf(The greatest common divisor is:%dn,x);void lcm(int x,int y)int temp,m,n;m=x;n=y;while(x!=0)temp=y%x;y=x;x=temp;printf(The lowest common multiple is:%dn,m*n/y);void main()int
33、 a,b;void (*p)(int,int);printf(Please input a and b:);scanf(%d%d,&a,&b);if(ab)p=gcd;elsep=lcm;(*p)(a,b);/xt050404.cpp#include stdio.hvoid main()int x,y; int sum(int,int),diff(int,int),product(int,int); void mma(int x,int y,int s(int,int); printf(Please input x,y:n); scanf(%d%d,&x,&y); printf(The sum
34、 of x and y is:); mma(x,y,sum); printf(The difference of xa nd y is:); mma(x,y,diff); printf(The product of x and y is:); mma(x,y,product); int sum(int x,int y) return x+y;int diff(int x,int y) return x-y;int product(int x,int y)return x*y;void mma(int a,int b,int s(int,int)int w;w=s(a,b);printf(%dn
35、,w);/xt050405.cpp#include double func1(int x),func2(int y);void main()double (*fptr)(int); /*定义指向函数的指针变量fptr*/int n;printf(input a number：);scanf(%d,&n);if(n1) if(n%2=0)fptr=func1;/*n为偶数，指针变量ptr指向函数func1()*/elsefptr=func2; /*n为奇数，指针变量ptr指向函数func2()*/printf(value=%9.4fn,(*fptr)(n);else printf(error!n);double func1(int x)int k;double value;value=1.0;for(k=2;k=x;k=k+2)value=value+1/(double)k; return value;double func2(int y)int k;double value;value=1.0;for(k=3;k=y;k=k+2)value=value+1/