《毕业设计—装配式钢筋混凝土简支T梁桥课程设计.pdf》由会员分享，可在线阅读，更多相关《毕业设计—装配式钢筋混凝土简支T梁桥课程设计.pdf（23页珍藏版）》请在三一文库上搜索。
1、? 1 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?!“#$%? ? ? ?A?BCD6?EFG?BCH6?I JKLAM/? ?JK)= ?v5? = ?v? ? ?e?ST ?)x5 ? 472 . 0 2/944 . 0 2 10 = q qm 431. 1 10 = r rm ?)t5 ? 5 . 02/000. 1 2 20 = q qm 0 021 = m v ? 639. 0 2 00. 1278. 0 2 30 = + = q qm 0 30 = mr ? 6 )?5 ?4STUVWX:;)?/5 ?89?U_?FG? 22.71 1.84 5 .19
2、 = = B l ECp?/JKUVWX:;mc“? ?STUVWX? fi ?#+?U?!?; fl nx?| ?uo? m aaaaaa i i 2 22222 5 1 2 32.40 )1.82- ( 1.8- 0 1.8 )1.82( 54321 2 22 2 = + = += = ? + = Ia Il i Ti i E G 2 2 12 1 1 pq?”?/?Jr?oot?svu?u? w? EGC C 4 . 0=$? 0.984 6.8948 2.89 32.4012 0.4 1 1 i 12 0.4 1 1 10 1019.5 a 2- 3-2 2 2 = + = + = I
3、 Il i Ti 1=p?“? ? ?i? = + = n i k ik a aa i n 1 2 1 1 ? ?L?R?UV? 0.5940.40.9840.2 32.4 0.984 5 11)1.82( 2 1 2 11 11 =+=+=+= = n i a aa i n -0.1940.40.984-0.2 32.4 0.984- 5 1 - 1)1.82( 2 1 2 151 15 = = n i a aa i n ?)t5?L?R?UV? 0.3970.1970.2 32.4 1.821.8 0.984 5 11 1 2 112 21 =+= +=+= = ? n i a aa i
4、n ? 7 0.0030.197-0.2 32.4 1.821.8 0.984- 5 11 1 2 52 25 = =+= = ? n i a aa i n v ?L?R?UV? 2 . 0 1 3531 = n ?#?UVWX?p?X?ST)? ?v5? ? ?v? ?v?JKSTUVWX:;mc)= ?t5? ? ? 8 = ?t? ? ? ? ? 1-5 ?-I ? ?mc 0.6300.679? ! ?“ 1#5$? ? % ? ABCD8? ? 6 7?EF?G/ kN QQQ 236.44 000 =+= ? =?HIJK?EF?G/ kN y a q mm q m Q r c r
5、 c r 24.925.0619.86 0.91630.679-1.431 2 4.9 9.7530.679)( 2 0 0 =+= +=+=? ? 9? ABCD89 ? ! 7?EF?G/ kN QQQ 252.55 000 =+= ? =?HIJK?EF?G/ kN y a q mm q m Q r c r c r 10.432.41-12.84 0.91630.439-0 2 4.9 9.7530.439)( 2 0 0 = +=+=? ? ? 12 :? ABCD8: 7?EF?G/ kN QQQ 296.43 000 =+= ? =?HIJK?EF?G/ kN y a q mm q
6、 m Q r c r c r 9.012.69-11.7 0.91630.4-0 2 4.9 9.7530.4)( 2 0 0 = +=+=? ? ?LM#$?NO?PQRS4 ?*4 ? T1? PQ?RS/UV?WX!Y?YZ W8BC_abcd?BC_a b?e?Gf ?BC?e?/2 . 1= Gi gh?BC?e?/4 . 1 1 = Q JK?BC?e?/4 . 1= Qj ?kN?m? (kN)? 1-8 ? )( 2 1 1 100 = += n j Qjk Qjc kQ n i Q Gik Gi udSSSS ? ? ? 1?2?3?4?5 Ml 2/ 818.01353.7
7、96.822686.697 Ml 4/ 613.51014.5171.662013.096 Ql 2 / 0137.284.97177.983 1 ? 5 Q0167.8236.4424.92504.258 Ml 2/ 851.81105.7862.602376.328 Ml 4/ 638.8829.3346.951782.185 Ql 2 / 0112.223.21144.633 2 ? 4 Q0174.72184.7810.43432.034 Ml 2/ 851.8858.8657.042059.604 Ml 4/ 638.8644.1342.781544.63 Ql 2 / 087.16
8、2.93112.775 3 Q0174.72296.439.01571.282 ?0? ? c? !“#? ? ? ! 13 ? ? ? ? ? ? ?M d? ?!“#$%?AB?C?DEFG )(5 .1195 .10130 0 cmah h = “# 1-1 $% T .130C89:1f cd =13.8MPa6 b77T R?= h b A f s ?O?i?() ?i?()fghFG n 3? cm b f b f x f hbfAf cd cd s sd 14.8 1813.8 1118-15013.8-84.7280 )( = = = ? ?i?3 ? ? ? ? .m2686
9、.697kNm2672.69kN. 2/11. 01.850.110.18-1.508 .13 0.148/2-1.1850.1480.188 .13) 2 ()( 2 10 10 3 3 0 0 = + =+= h hhb f h f M f cdcd df b f x bx ?4?i?*+? ? ? ?E 4 ?3?3!“#-(?%&789:?A? BC?%&?D? ?EF?G*?HI!J?K?LMN?!J?OPQR?h0S)!J?TUVW ?XY JCIZ?K!S? O?4? .?M 13? ? ? mkN x hAfM s s .633.30 2 0.148 -1.18510.1792
10、802 ) 2 (2 1010 4-3 011 = = = O?4O .?M 13? ? ? mkN x hA f Ms s .40.005 2 0.148 -1.185043. 82802) 2 (2 1010 4-3 022 = = _%&?D?EMaA ? 17 ? ? mkN x M hA f s s .85.2634 2 0.148 -1.18570.84280) 2 ( 1010 4-3 02 = = #? ? ?”? ?N? HIJKLBAOA? KP?()IU?T ? O? ? bO4B?MPa f sv 195=c ? Cij cmAsv 2 006. 1=d ? A?BA4
11、 )CDE%?FEGHI%&-JK ?A4?L 0013. 0)/(,018. 3 2 =bh A cm Ass ? MN O-OOP?BO?OO? QR?SF- ?TUVWX?YKWZ?( ?_?P ? ?_? ?5a MPa MPa s cr s cr B E f WS W f M B B M M M M B c tk tk cr cr 10 )()( 4 00 0 0 22 0 0 . 3 2.01 /2 1 = = = + = ? bcaS0ddefgh!ijk%lmfgnopFqrstnop)guv- ?wddmfgcxpy z 6g)y|-w ?b+a 0)()( 2 1 2 1
12、0 2 1 2 1 )( = xnb hA tx bxb s ?a ? 20 mmcmx x x x xx 2544 .25 085.1832204 0)118.5(84.70.667)18180( 2 1 180 2 1 2 2 2 )11( = =+ = ? ? ? ? m S 3767 0 101010 5.11681.866244.9302 2 110-254 180110-254110/2-2541101800 =+= += efgtno)?xva ?mm I 410 010 8948. 6= efg?%?x?va ? ? mmN W f M WS mmxhIW tk cr .057
13、. 2 382. 1/2 7.4058)254-1185/(8948. 6)/( 10 1010 8 0 00 2710 0000 = = = Icrk%fg)?xv?b?a mm tx bxb x hAI bn scr 41010 3 3 2 3 1 3 1 2 1010 )110254( 254 )2541185( )()( 5.716540.16124-0.983224.89456 )1801800( 3 1 1800 3 1 84706676. )( 3 1 3 1 0 =+= += += ? mmNmkN c c M I EB I EB s cr cr .86241 . 1 .41.
14、1862 1.9650.95 715 . 1 10 10 10 9 15 0 0 15 = = = ? mm B B M M M M B N s cr s cr B cr 215 15 15 22 15 0 22 0 .1.6819 1.715 1.965 9 8 1 9 8 1.965 1 10 10 10 ) 10 86241. 1 10 057. 2 () 10 86241. 1 10 057. 2 ( 10 )()( = + = + = ?q?)? )?nHI)$?v?vM GK 4P4?HI)$ ?)?vh!?l= Mqk PO?P?3 ?HI)$?vM rK ?2?4? ? hPl
15、?6)? ?5?6)?!? ?nHI)?(?!? ?-LS?HI)c?(a ? 21 ? ? ? 25. 3 600 1950 600 11. 30.0311 1.681948 82.961041.37 . 05 6 . 1 48 5 6 . 1 10 19.510 0.7 9 23 2 cm L cmm B f LMMrK qk = + = + ? ?3? ?*+?(? ?n P? S?HI)? (- ? ? ? 64. 40464. 0 48 ) 5 6 . 1 48 5 6 . 1 2 2 0.7( 2 1 2 1 cmm B GK B GK f LMMMLM M rK qk = + =
16、 = + ? ? t”?6)?6?6c)6?$?6cfg? ?$!?*?c6cR)?6Se?- PT5?K?c6q)?atc6)$!?= ?P ?- ?P?c6)?h?a?l CD?tc6)?a ?v?akNy pq P kk oq 144.46)1.02381.024.85 2 1 5 .10( 2 1 )( 2 1 =+=+= ?akN Poq 173.35144.461.2= ?T?c6cR)? ?g?o?S?)? PT? 6)Ds? ? ? 22 L Mr)?S?a ?P ?K? P 6pq/h-0.1940.594 1511 = ?l a -0.7471.821-1.810.3971
17、.82945 . 0 211.02 2111 1 =+= +=ddd M r ?P ?K? _ 6pq/a -0.6861.810.0031.820.194- 1.02 5251 5 =+= += ? dd M r Mr)?S?a ?P ?K? ? 6pq/h0.2990.397 2212 = ?l a ? 23 671 . 01.811-1.81.0299 . 0 1.820.397 111.02 2221 2 =+= +=ddd M r ?)S?M r ? ? fg?M r5 M r3 ? ? ? fg?= M rr ?S?M r ? ? ?- ?3T? ?$!?=?9 P 6)?h?9
18、_ 6)?l -t P ?6fg) Q?1?S?a ?P ?K?fgF?a Q?1?R1 ? i1 1i = ? ?P ?K?fgF?a 1 1 1 =R Q? ?1 1 1i = i ? ?Q? 1 ? ? ?Tfg? +?)?Poq?1)?q$!?=?t? ?+1?L? ?P ?- ? ?P ? M3 mkN PMoq .239.090.1981.081144.461294. 1)1 ( 3 =+=+= ? ? ? ? ? Q?1 mkN PQoq .282.640.0470.2440.3860.583173.35294. 1)1 ( 1 =+=+= ? ? _T?fl ?h?6)? ?n?cS?!?l a ? P T?WZ?fl ?h? ?l ? ? mkN Mr .334.726239.094 . 10 max, =+= ? mkN Q i .395.70282.644 . 10 max, =+= ? ? 2 T?YK?WZ?fl ?h? ?3l ? ?3 mkN Mr .129.3494239.09/1.20.70 max, =+= ? mkN Q i .152.9094282.64/1.20.70 max, =+= ?