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1、YXOChapter 10 Exercises:10. 5 a) b)Zc) The vector torque produced by this force is 10.12 a) Using the free-body-diagram, we get the equations about bucket and cylinder.TRmgT+Y (1) (2) (3) (4) (5)The tension is T = 42.0Nb) Using the mechanical energy conservation, we get;c) From the equation (1), we
2、know the acceleration of bucket is .So we can get the time is .d) While the bucket is falling, the weight of cylinder and the support force of pivot exert on the axle.T2N10-13T1T1MgT2mgThe free body-diagram for the bookThe free body-diagram for the pulleyThe free body-diagram for the textbook For th
3、e textbook, according to the Newtons second law on the horizontal direction, the equation is (The positive direction is to right.) (1)For pulley, the equation is (The clockwise direction is positive rotation.) (2)For the book, the equation is (The positive direction is downward.) (3) (4) (5)Because
4、the forces are constants, the acceleration a is a constant value.We find . As the initial conditions, , so at time t = 0.800s, the acceleration is . Put as value into the equation (1), the tension between the textbook and the pulley is . Put as value into the equation (3), the tension between the pu
5、lley and the book is .Put T1 and T2 into the equation (2), the moment of inertia of the pulley is ; .10-21 a) After this 15.0s interval, the angular acceleration is . So the angular velocity after this 15.0s interval is (At t = 0, it is at rest).b) After this 15.0s interval, the merry-go-round has r
6、otated angle which is .So the work done by the torque is .c) The average power supplied by the child is .10-28 The womans moment of inertia respect to the center is . The disks moment of inertia respect to the center is .So the total moment of inertia is .The angular momentum of the woman-plus-disk
7、system is 10-33 a) The angular momentum of the block is conserved. When the block is revolving on the surface, the total torque on the horizontal direction is zero.b) According to the conservation of angular momentum, the new angular momentum is . c) When the blocks angular velocity is 1.75rad/s, th
8、e kinetic energy is .When the blocks angular velocity is 7.00rad/s, the kinetic energy is.The change in kinetic energy of the block is .d) The work done by the pulling force is .10-73 When the bullet collides with the target, the angular acceleration of system will be conservation. (1)The moment of
9、inertia of the bullet is .The moment of inertia of the target isThe total moment of inertia of the system is .b) According to the conservation of mechanical energy, we get; .c) If the board is swing all the way after impact, the center of mass will up the height that is 0.250m. So we get; .Using the equation (1), we get4