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1、110kVXX输变电工程电缆护套感应电压计算（隧道）资料准备：本工程一回110kV电缆极限输送容量：135MW功率因数：0.9则输送电流 I ： p 二 135000-787.3Av3 <U hcos® J3X110乂 0.9电缆截面：1000mm2电缆外径：101.3mm（参照中天科技海缆有限公司产品样本）则护套的几何平均半径 GMRS = 101.3 09 = 45.585mm2 =2：f =2 3.14 50 =314.两回垂直排列4004001. A相护套感应电压AB = S = 400mmAC = ns 二 800mm 推出n = 2推屮AA 二 PS = 300mm
2、> P =0.75AB =qS 二 3002 4002 = 500mm 推出q =1.25AC =rS 二 3002 8002 = 854.4mm 推出r =2.136根据公式Esa=2I勺0° |工31n空+j丄InnqS7 "代入参数2 q 2(PPMRs 匚推出Esa=2 314 787.3 10,InSjg + j1"2".25"136 律oo2】1.252(0.7545.585 2.295V km取模= 49.442441.0643j3.297 =52.6216j163.012> ESA =1712. B相护套感应电压BA
3、 二 S = 400mm推出.BC 二 mS =400mmm = 1BA 二 q S 二 500mm 推出q = 1.25推出BB 二 tS = 300mmt= 0.75推出BC 二 yS 二 500mm 推出y =1.25Esa=2 1 10*Inmsyt GMRs1-j2Inq2S 1mtyGMRs=49.44244In mSy| 2 t GMRS1-j In2q冬 mtyGMRs=49.442441 400 1.250.75 45.585-jiIn1.252 x4001X0.75X1.25X45.585= 49.442442.3233 - j1.3414 = 114.87 - j 66.
4、322EsbA132%3.C相护套感应电压推出AC =nS = 800mmn = 2推屮BC=mS= 400mm* m = 1CA = AC =rS=854.4mmr =2.136CB = BC'nyS =500mm推出y =1.25CC JzS=300mm 推出z =0.75Esc=2 I 10-dn_ 2msy2 GMRSJin "2 my"zxGMRS= 49.44244 十虫 In 1 如。"药“丄“厅“136 很 40022 汉 45.58521 汉1.25 汉 0.75 疋 45.585=49.442441.474 - j2.57 - -72.
5、872 - j127.082Esc 卜 146.493Vkm二.两回三角排列（一）4004001.A相护套感应电压AB = S = 300mmAC =nS = 500mmn =1.667推出AA 二 ps=400mm 推出p =1.333AB = qs = 800mm 推出q = 2.667推出AC J rS = 854.4mm 推出r =2.848Esa =2国1 如。'叵 In 匹+ j1 InnqS_2-2 q 2(pxGMRs)1.333 45.585 2= 49.44244 "回n 1 聞"848 + j 1 “ 匸667 狀 26贰 284 如】 22.
6、6672=143.837=49.442440.499 j2.866 =24.672j141.7055Esa2.B相护套感应电压BA = S = 300mmBC =mS =400mm 推出 >m =1.333BA =qS= 500mm 推出,q = 1.667推出BB =ts = 854.4mmrt =2.848BC '= ys =800mm 推出ty =2.667q'2Sesb®35Vkm21.667300Esb=2 J 10TnHGMRrj1InmtyGMRs = 49.44244 込n® 300 喻-j11n|L 22.848 45.58521.3
7、33 2.848 2.667 45.585= 49.442441.823 j0.2956 = 90.173 - j14.61653. C相护套感应电压推出AC =nS = 500mmn =1.667推出CA = r S = 300mm推出CB J yS =500mm 推出）y'T.667推出CC = zS = 400mm z =1.333ESC =2 J 10 - 3msyInj22 GMRSn2r2S1 In2 myz GMRS2 21.6671300= 49.44244 亠j 1 300 1.667. 1 ,-Inj In21.333 45.58521.333 1.667 1.33
8、3 45.585=49.44244-1.8254 - j0.9102 =90.252 - j 45ESC|=100.85%m.两回三角排列（二）4004001. A相护套感应电压AB = S = 300mm推岀AC = nS =500mm 推岀n -1.667，推出AA = ps =854.4mm、p=2.848AB = qs 二 800mm 推出q = 2.667AC= rS= 400mm 推出r =1.333Esa =2 I10,迢n_2nrqj2Inn qrS2(pPMRsf 一= 49.44244 In|L 22.6671 1.667 咒2.667 X1.333X3002_ In32
9、(2.84845.585 f= 49.44244-0.158 j 1.7273 二-7.868j85.4=85.763BC =mS =400mm 推出m = 1.333BA =qS =800mm 推出q =2.667推出BB 二 ts = 854.4mmt = 2.848BC ' = ys = 500mm 推出y =1.667q"2sEsb =2 I 10鼻In 皿 j11n2 t GMRs2 mtyGMRst GMRs2.6672 300= 49.44244 笛n® 3°° 倔7,"| 22.848 45.58521.333 2.84
10、8 1.667 45.585= 49.442441.417 -j1 = 70.06 - j 49.468esb=85.7643.C相护套感应电压推出AC = nS =500mm 推出 n =1.667BC =mS =400mm 推出 >m =1.333推出CA =rS =400mm rr =1.333CB 二 y S=500mm 推出y = 1.667esa2. B相护套感应电压BA = S = 300mmCC = zS 二 300mm 推出Esc =2 I 10，亠In22 GMRsn2rr2S2 my GMRs近=49.44244InI 2=49.44244-2.323£詛=132.627孩口1.333 300 1.66711.6672 1.3332 300i In1x45.58521.333x 1.667x1x45.585-j1.341 = -114.855-j66.319