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1、附录八 标准电极电势()1.在酸性溶液中电极反应E/V电极反应E?/ VAg" + e- = Ag-6Cd，+ + 2e = Cd(Hg)Ag + e = AgCe + 3e = CeAgAc+e = Ag+AcCl2(g) + 2e = 2ClAgBr+e = Ag+ Br33HCIO+ H + e = 1/2C1 2+ fOAgBrO+ e = 2Ag+ BrOHCIO+ H + 2e = Cl + H2OAgOO + 2e = 2Ag+ C2o27CIO2+ H+ +e = HCIOAgCl + e = Ag+ ClHCIO + 2H+ + 2e 一 = HCIO+ HOAg
2、CO3 + 2e= 2Ag+ CO2-HCIQ+ 3H1 + 3e = 1/2CI 2 +2H2OAgCrO+ 2e = 2Ag+ Cro20HCIO+ 3H十 + 4e = Cl +2H2OAgF+ e- = Ag+ F-CIO3 + 2H' + e = CIO2+ H2OAg I +e = Ag+ I24CIO 3 + 3HT + 2e =HCIO+ HOAgS+ 2H+2e =2Ag+fS6CIO 3 + 6H' + 5e =1/2CI 2 +3H2OAgSCN- e- =Ag+ SCN51CIO 3 + 6H+ + 6e =CI +3讯0AgSO+ 2e = 2Ag+
3、So；CIO4 + 2HT + 2e =CIO3 + HtO3十Al +3e =AlAlF 36 +3e =Al+6FCIO 4 + 8H十 + 7e = 1/2CI 2 +4冲0AaO+61十 +6e =2As+3HOHAsO+3H+ +3e =As+2H0CIO 4 + 8H+ + 8e =CI +4H2OHAsO+21十 +2e=HAsO+2HOCO + 2e = CoAu十 +e=AuCcT + e一 =C6+ (2mol L 1 H2SO)Au3+3 e =AuCQ+ 2H+ 2e = HCOOHAuCl4 + 3e = Au+ 4Cl2+ Cr + 2e = CrAu3+ + 2e
4、 = Au+3+ 2+Cr + e = CrHBO+ 3H十 +3e = B+ 3f08Cr3+ + 3e = Cr2+ 一Ba + 2e = Ba+3+CcO； + 14H + 6e = 2Cr + 7fOB+ 2e 一 = Ba(Hg)HCrO + 71十 + 3e = Cr3+ + 4fOBe+ 2e = BeCu+ + e 一 = CuBiCl -4+ 3e = Bi + 4Cl cf + e =Cu+Bi2O+ 4H+ +2e = 2BiO+ + 2H2OCu + 2e = Cu9BiO+ 2H+ +3e = Bi + 甩0CuCI + e = Cu+ ClBiOCl + 2H+ +
5、 3e 一 = Bi + Cl + f O3F2+ 2H+ + 2e 一 = 2HFB2(aq) + 2e =2Br3F2 + 2e = 2FB2(l) + 2e 一 = 2BrFe2+ + 2e = FeHBrO+H+ + 2e = Br + H2OFe3+ + 3e = FeHBrO十 H十 + e一 = l/2Br 2(aq) + WO3+2+Fe + e = FeHBrO+H+ + e = l/2Br 2(1)+ H2OFe(CN)6 - + e =Fe(CN) 6"一BrO3 + 61十 + 5e = l/2Br 2+ 3甩0FeO；- + 8H+ +3e 一 =Fe
6、9;+ + 4HOBrOs + 61十 + 6e = Br + 3HOG+3e =GaCa + 2e = Ca2H+ + 2e = HCcT + 2e 一 = CdH(g) + 2e 一 = 2HCdSO十 2e = Cd+SO：HQ+ H+ + e 一 = I4Q电极反应E?/ V电极反应E?/ VHO2十 2hT 十 2e = 2H2O2丄O+ 4H丄 + 4e = 2htOHg+ 2e = HgO(g) + 2H丄 + 2e = HO2Hg21 + 2e = Hg2+O+ 2H，+ 2e = O + HOHg2+ +2e = 2Hg3P(red) + 3H+ + 3e = Phl(g)H
7、gB2+ 2e = 2Hg+ 2Br23P(white) + 3H + 3e = PH(g)HgCH 2e = 2Hg+ 2Cl08HPO+ H + e = P+ 2HOHg” 2e =2Hg+ 2I5HPO+ 2H + 2e = H3PO+ HOHgSO+ 2e = 2Hg+ SO25fPO+ 3H1 + 3e = P + 3HOI2+ 2e =2I5HPO+ 2H + 2e = H3PO+ fOI3 - + 2e 一 = 31Pb2+ + 2e = Pb2H5IO6+ H1 + 2e = IO3 + 3H2OPbBr2 + 2e = Pb+ 2Br2HIO+2H 丄 +2e = 2+ 2H
8、0PbCl2 + 2e = Pb+ 2Cl5HIO+ H+ + 2e = I +H2OPbF2 + 2e = Pb+2F42I0 3 + 12H' +10e = I2 +6H2OPbI2 + 2e = Pb+2IIO 3 + 6H + 6e = I + 3H2OPbO + 4H+ + 2e =戸丄+2讯0In +2e = InPbO+ SO2- + 4H1 + 2e = PbSO+ 2H2O3In "丄 + 3e = In2PbSO+ 2e = Pb+ SOT8Ir 3 + + 3e = IrPcT+ + 2e= Pd£ + e = KPdCl 2- + 2e =
9、Pd+4ClLa 3+ + 3e = LaPt2+ + 2e = PtLi 丄 + e = Li1RtT + e = Rbz丄Mg + 2e = MgRe + 3e = ReMH丄 +2e_ = MnS+ 2H+ + 2e = HS(aq)Mri丄 +e" = Mn +S2O6 + 4H 丄 + 2e =2H2SOMnO+ 4J + 2e= m6丄 + 2fOSO8 + 2e = 2SO4-Mn04 + e" =MnO-SO8 + 2H+ + 2e =2HSOMn。； + 4H+ + 3e= MnO+ 2HO2HSO + H+ + 2e = H2SO + 2f0Mn O4
10、+ 8H+ + 5e= M(+ 4fOfSO+ 4H+ + 4e = S + 3HOMO丄 +3e= MOSO2- + 4H+ + 2e = HSO + fON+ 2fO+ 6rf + 6e= 2NHOH2SO4 +4H+ +2e = SO； + 2HO3N2 + 2H+ 2e= 2NH(aq)Sb+ 3H+ 3e = 2SbH>NO+ 2H+ + 2e= N2 + 冲0SbO+ 6H+ + 6e = 2Sb+ 3H2ONO4+ 2e= 2NQSbQ+ 6H + 4e = 2SbO + 3H2ONO*+ 2H+ + 2e= 2HNOSbO丄 + 2H+ + 3e = Sb+ f O丄NO
11、+ 4H + 4e = 2NO 2WO3+Sc + 3e = Sc2N6 2H+ + 2e= N2O+ H2OSe+ 2H+ 2e = WSe(aq)HNO+ H+ e= NOH H2OfSeO + 4H+ +4e = Se+ 3HO2HNO丄 4H" + 4e= N2O+ 3HO2 丄一SeO +4H +2e = fSeO + H2ONC3 + 3H+ + 2e=HNO+ H2OSiF 2 +4e =Si + 6FNO3 + 41丄 + 3e= NOH 2HQ(quartz)SiO 2 + 4H+ + 4e = Si + 2甩02NO3 + 4H+ 2e= N2O+ 2HOSn2+
12、 + 2e = Sn5Na + e = Na_. 4+ _ 2 +Sn + 2e = SnNb>+ 3e 一 = NbSr 丄 + e 一 = SrNi2+ 2e_ = NiSr2+ + 2e = Sr丄2 +NiO+ 4H + 2e = Ni + 2HO2+Sr + 2e = Sr(Hg)O+ 2H+ +2e = HOTe+ 2H+ 2e 一 = HTe电极反应E/V电极反应E/VTe + 4e = TeV3 + e = VTeO+ 4H* + 4e = Te+ 2H0V(5' + 2H" + e- = V' + H2OTe O4 + 8H+ + 7e = T
13、e+ 4HH0VO； + 2H+ + e- = VO + fOHTeO+ 2H* + 2e = TeO+ 4 WOV(OH) 4 + 2H+ + e- = VO+ + 3HOTh4+ + 4e= ThV(OH) 4 + 4H+ + 5e- = V+4H2OTi2十 + 2e = TiW + 214 + 2e- =2W(2+ HO 3十-Ti + e = TiW<2+ 4H+ +4e- =V+ 2fOTi02+ + 21+ + e- =Ti 3+ H2OWO+ 6H+ +6e- =V+ 3H2OTiO2+ 4H+ + 2e-= Ti2+ + 2fO2W(3+2H+ +2e- =WO+ H2
14、OTl + + e- = TlY3+ + 3e- = YV+ + 2e- = VZn2+ + 2e-= Zn81.在碱性溶液中电极反应E7 V电极反应E/ VAgCN+e = Ag+ CNCu(0H)2+ 2e = Cu+ 20HAg(CN) 2 + e = Ag+ 2CN2Cu(0H+2e = CuO+ 20H + H2OAgO+ H2O+ 2e = 2Ag+ 2OHFe(CN) 6 3 +e =Fe(CN)642AgO H2O+ 2e- = Ag2O+ 2OHFe(0H)3+ e = Fe(0H)2+ OHAgS+ 2e = 2Ag+ SHtGaO + HO+ 3e = Ga+ 4OHHA
15、IO3- + fO+ 3e- = Al + 4OH2H0+ 2e- = f + 20H7As o2 + 2HO+ 3e = As+ 4OHHgO+ HO+ 2e = 2Hg+ 20HAsq + 2H2O+ 2e = Aso2 + 40HHgO+ HO+2e =Hg+ 20H7HBO, + 5fO+ 8e = BIH +8OHHd 03- +2e = IO3 + 30HHBO3 + HO+ 3e = B+ 4OHIO + HtO+2e =I + 20HBa(OH) + 2e- =Ba+ 2OHI03- + 2H0+ 4e- = IO- + 40HBe o； + 3HO+ 4e = 2Be+ 6O
16、HIO3 + 3HO+ 6e = I + 60HBi 203 + 3H2O+ 6e- = 2Bi + 6OHIr 203+ 3H2O+ 6e- = 2Ir + 60HBrO- + H=O+ 2e- = Br - +2OHLa(0H)3+ 3e- = La + 30HBr 03 + 3HIO+ 6e = Br + 6OHMg(OH+ 2e- = Mg+ 20HCa(OH) + 2e- =Ca+ 2OHMnO- + 2HO+3e- = Mn<2+ 40HCa(OH) + 2e =Ca(Hg) + 2OHMno4 +2H0+ 2e = MnO+ 40HCIO- + HO+ 2e- = Cl -
17、 +2OHMn(OH)+ 2e- = Mn+ 20HCl 02 + H20+ 2e- = CIO- + 20HMn(OH+ e = Mn(OH)+ OHCl 02 + 2H0+ 4e- = Cl- + 40H2N0+ HO+2e- =NQ+ 20HCl o3 + fO+ 2e- = Cl 02 + 20HNO H2O+ e- = NOH 20HCl o3 + 3H0+ 6e- = Cl- + 60H2N0- + 2HO+4e- = n2 +40HCl o4 + H.0+ 2e- = Cl o3 + 20H2No2 + 3HtO+4e- = N2O+6OHCo(NH) 6 3+ + e- = C
18、o(NH3)62 +NQ + H20+ 2e- = NO- + 20HCo(OH) + 2e- =Co+ 20H2No3 + 2FtO+2e- = NQ + 40HCo(OH) + e- = Co(OH) + OHNi(0H)2+ 2e- = Ni + 20HCro； + 2H0+ 3e- = Cr+ 40HNiO2 + 2fO+ 2e- = Ni(0H)2 + 20HCroj + 4H2O+ 3e- = Cr(OH”+ 50HO+ H0+ 2e- = HO- + OHCr(0H)3 + 3e- =Cr+ 30HO+ 2H<+ 2e- = H2O +20HClj + 2CN + e- =
19、 Cu(CN) 2O+ 2HtO 4e = 40HCu(CN)2- + e- = Cu+ 2CNO+ H0+ 2e- = 0+ 20HCuO+ H0+ 2e- = 2Cu+ 20HHO- + HO+ 2e- = 30H电极反应E?/ V电极攵反应w/vP+ 3H2O+ 3e =PH(g) + 30H2S03 +3H20+ 4e=So： + 60HHPQ + e = P+ 20HS 02 + H20+ 2e =S03 + 20HHPO3 + 2H2O+ 2e = H2Po2 + 30HSb。2 + 2H0+ 3e=Sb+ 40HHPo2 + 2H2O+ 3e = P+ 50HSb。，+ H20+
20、 2e = SbQ + 20HPo： +2H2O+ 2e = HPq + 30HSe。； +3H20+ 4e=Se+ 60HPbO H0+ 2e = Pb+20HSe04 +H20+ 2e=Se02 + 20HHPb(0 + H20+ 2e = Pb+ 30HSi 02 + 3H20+ 4e=Si + 60HPb0+ H20+ 2e = Pb0+ 20HHSn0 + H0+2e=Sn+ 30HPd(0H) + 2e - =Pd+ 20HSn( 0H)2 + 2e=HSnQ + 30H+H20Pt(0H)2 + 2e =Pt + 20HSr(0H) + 2e = Sr + 20HRe0+ 4H0+ 7e= Re+ 80HTe+ 2e = Te"S+ 2e = S27Te 02 +3H20+ 4e=Te+ 60HS+ H20+ 2e= HS + 0HTh(0H)4+ 4e= Th + 40H2S+ 2e= S236Tl 2O+ 3H20+ 3e=2Tl+ + 60HS 0：- + 2e =2S 0Zn 0； +2H0+ 2e=Zn+ 40H2S& + 2H20+ 2e= 9 & + 40H摘自 of Chemistry and Physics,