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1、兼职工程师考试题居住地： 姓名： 选择题分数： 问答题分数： 一、选择题：1、 下列哪些设备可以用来划分网段：（ e ）A、hubB、repeaterC、switchD、bridgeE、routerF、media converters那些设备可以用来分隔局域网：（ c,d ）2、 下列那个地址是单播地址：（ ）A、224.1.5.2B、FFFF.FFFF.FFFFC、192.168。24.59/30D、255.255.255.255E、172.31.128.255/183、 网线常见线序有直通线、交叉线、反转线三种做法，请把下列设备分类，并指出类别内及类别间连接所使用的线路类型：HUB SWI
2、TCH ROUTER PC CONSOLEAnswer:1、( ) ；2、( )；3、 ( ) 4、 对以下路由协议进行分类，并写出各类的路有协议类型：（ ）RIPV1 RIPV2 IGRP EIGRP OSPF ISIS5、 下列那些路由协议支持VLSM和路由汇总： （ ）IGRPRIPV1RIPV2EIGRPOSPFISISVTPCDP6、 下列哪条访问控制列表会阻止所有到10.10.1.0/24网段的telnet请求：（ ） A. access-list 15 deny telnet any 10.10.1.0 0.0.0.255 eq 23 B. access-list 115 den
3、y udp any 10.10.1.0 eq telnet C. access-list 15 deny tcp 10.10.1.0 255.255.255.0 eq telnet D. access-list 115 deny tcp any 10.10.1.0 0.0.0.255 eq 23 E. access-list 15 deny udp any 10.10.1.0 255.255.255.0 eq 237、 Which IP address and wildcard mask would you use in your ACL to block all the hosts in t
4、he subnet 192.168.16.43/28? （ ） A. 192.168.16.32 0.0.0.16 B. 192.168.16.43 0.0.0.212 C. 192.168.16.0 0.0.0.15 D. 192.168.16.32 0.0.0.15 E. 192.168.16.0 0.0.0.31 F. 192.168.16.16 0.0.0.318、 A standard IP access list is applied to an Ethernet interface of a router. What does this standard access list
5、filter on? （ ） A. The source and destination addresses B. The destination port number C. The destination address D. The source address E. All of the above9、 A brand new network application is required for the Acme Company, and they are considering the use of a connectionless service. What are the ch
6、aracteristics of a connectionless service? (两项) （ ） A. It uses a Reliable transport mechanism. B. It uses a Non-reliable transport mechanism C. It is less bandwidth-intensive than connection oriented services D. it uses handshaking10、 The TestKing network is implementing dialup services for their re
7、mote employees. TestKing uses several different Layer 3 protocols on the network. Authentication of the users connecting to the network is required for security. Additionally, some employees will be dialing long distance and will need callback support. Which protocol is the best choice for these rem
8、ote access services? （ ） A. 802.1 B. Frame relay C. HDLC D. PPP E. SLIP F. PAP11、 TestKing has 25 computers and decides to connect the network to the Internet. TestKing would like for all of the computers to have access to the Internet at the same time, but TestKing only has four usable publicly rou
9、table IP addresses. What should be configured on the router so that all computers can connect to the Internet simultaneously? （ ） A. Static NAT B. Global NAT C. Dynamic NAT D. Static NAT with ACLs E. Dynamic NAT with overload12、 Which of the following describe private IP addresses? (Choose two) （ ）
10、A. Addresses chosen by a company to communicate with the Internet. B. Addresses that cannot be routed through the public Internet. C. Addresses that can be routed through the public Internet. D. A scheme to conserve public addresses. E. Addresses licensed to enterprise or ISPs by an Internet registr
11、y organization.13、 What parameters must you specify when you enable EIGRP routing? （ ） A. The broadcast address, and AS number B. The network number and AS number C. EIGRP routing, network number and passive interface D. EIGRP routing, network number, and AS14、 Which of the following addresses can b
12、e assigned to a host when using a subnet mask of 255.255.254.0? (Select three) （ ） A. 113.10.4.0 B. 186.54.3.0 C. 175.33.3.255 D. 26.35.2.255 E. 152.135.7.0 F. 17.35.36.015、 You need to set the default gateway of one of your TestKing switches. Which command will set the default gateway to 192.168.12
13、.1 on a Cisco switch? （ ） A. Switch(config)# ip default-network 192.168.12.1 B. Switch(config)#ip route-default 192.168.12.1 C. Switch(config)# ip default-gateway 192.168.12.1 D. Switch(config)# ip route 192.168.12.1 0.0.0.016、 What is the purpose of the command shown below? ip route 0.0.0.0 0.0.0.0
14、 serial0/0（ ） A. It configures a router to send all packets out interface serial 0/0. B. It configures a router to block routing updates from being sent out interface serial 0/0. C. It configures a router as a firewall, blocking all unauthorized packets from exiting serial 0/0. D. It configures a ro
15、uter to send all packets for unknown destination networks outinterface serial 0/0. E. It configures a router to drop all packets for which the destination network is unknown. 17、 A Class C network address has been subnetted with a /27 mask. Which of the following addresses is a broadcast address for
16、 one of the resulting subnets? （ ） A. 201.57.78.64 B. 201.57.78.87 C. 201.57.78.33 D. 201.57.78.254 E. 201.57.78.159 F. 201.57.78.9718、 在Serial x is down, line protocol is down的情况下可能是哪些故障造成：（）A 载波没有收到B 线缆出现问题C Clock rate在DCE端没有设置D 服务提供商造成的ERROR RATE过高19、 在Serial x is down, line protocol is down的情况下可
17、能是哪些故障造成：（）A 载波没有收到B 线缆出现问题C Clock rate在DCE端没有设置D 服务提供商造成的ERROR RATE过高20、 请参看一下配置：Figure 1-1 Output of the HDLC show interface serial CommandTable 1-1 shows the interface status conditions, possible problems associated with the conditions, and solutions to those problems.Serial 0 is up, line protoco
18、l is upHardware is MCI SerialInternet address is 131.108.156.98, subnet mask is 255.255.255.240MTU 1500 bytes, BW 1544 Kbit, DLY 20000 usec, rely 255/255, load 1/255Encapsulation HDLC, loopback not set, keepalive set (10 sec)Last input 0:00:00, output 0:00:00, output hang neverLast clearing of show
19、interface counters neverOutput queue 0/40, 5762 drops-A; input queue 0/75, 301 drops-BFive minute input rate 9000 bits/sec, 16 packets/secFive minute output rate 9000 bits/sec, 17 packets/sec5780806 packets input,785841604 bytes, 0 no bufferReceived 757 broadcasts, 0 runts, 0 giants146124 input erro
20、rs-C, 87243 CRC-D, 58857 frame-E, 0 overrun, 0 ignored, 3 abort5298821 packets output, 765669598 bytes, 0 underruns0 output errors, 0 collisions, 2941 interface resets, 0 restarts2 carrier transitions通过以上条目判断出：( )A 接口的硬件有问题B input drop发生在串行接口上可能因为：输入速率超过路由器处理能力。C 输入和输出队列都属于硬件特性,一般设备不能提供修改。D 可以用hold-
21、queue in进行调整输出队列21、 有一种对于线路的测试为“环路监测”，根据下图标注出了环路监测是原理，请选出正确的一个：( )ABCD22、 通过下面显示，最终显示为接口down的原因是由于：（ ）Figure 1-2 debug serial interface Command Outputrouter# debug serial interfaceSerial1: HDLC myseq 636119, mineseen 636119, yourseen 515032, line upSerial1: HDLC myseq 636120, mineseen 636120, yourse
22、en 515033, line upSerial1: HDLC myseq 636121, mineseen 636121, yourseen 515034, line upSerial1: HDLC myseq 636122, mineseen 636122, yourseen 515035, line upSerial1: HDLC myseq 636123, mineseen 636123, yourseen 515036, line upSerial1: HDLC myseq 636124, mineseen 636124, yourseen 515037, line upSerial
23、1: HDLC myseq 636125, mineseen 636125, yourseen 515038, line upSerial1: HDLC myseq 636126, mineseen 636126, yourseen 515039, line upSerial1: HDLC myseq 636127, mineseen 636127, yourseen 515040, line upSerial1: HDLC myseq 636128, mineseen 636127, yourseen 515041, line upSerial1: HDLC myseq 636129, mi
24、neseen 636129, yourseen 515042, line upSerial1: HDLC myseq 636130, mineseen 636130, yourseen 515043, line upSerial1: HDLC myseq 636131, mineseen 636130, yourseen 515044, line upSerial1: HDLC myseq 636132, mineseen 636130, yourseen 515045, line upSerial1: HDLC myseq 636133, mineseen 636130, yourseen
25、515046, line downA 链路发生噪声B CRC循环交验错误C 线缆出现问题D Keepalive信号错误23、 在实现密码恢复后，以下哪些进行修改操作：（ ）A 修改寄存器值B 修改NVRAMC 修改BOOT FLASHD FLASH24、 对原有设备进行IOS升级操作，原有设备show flash如下图：能否加载32Mflash和32M RAM的IOS：答案： 25、 确定路由器正确的启动顺序：（ ）A ROM, T, FlashB Flash, T, ROMC Flash, NVRAM, TD Flash, ROM, TE Flash, T, RAM26、 请配置本路由器为t
26、 IOS为gs7-k.9.17，只允许172.16.101.0网段的机器进行TFTP请求。请试写如下配置：27、 请将当前配置和初始配置上传到服务器172.16.2.1的config文件中：28、 在2500设备上当输入 O/R 0x2142命令进行密码恢复的目的是：( )A 重新启动路由器B 启动时不从NVRAM中读取配置文件C 用于进入ROM状态D 保存配置修改29、 让路由器进入安装模式的问题是：( )A 配置文件在NVRAM中间丢失B 配置码改为0x2100C Boot system命令在run-config 中间丢失D IOS 丢失30、 在桢中继网络中，在点对点子接口中需要配置：(
27、 )A 桢中继在物理子接口的封装B 在每个子接口的DLCI号C IP地址在物理接口下D 子接口建立的类型为点对点二、问答题：1、如何更换switch的IOS？ 写一下基本命令2 、如何更换router的IOS，说出一种方法和必要的命令3 、如果上传IOS过程中，IOS文件损坏，router无法正常启动，如何处理，请简单描述。4 、路由器以WIC-1T与专线连接，当出现故障，DCD 指标是down的时候说明了什么问题？5、查看路由器广域网端口的指标是以下情况DCD=up DSR=up DTR=up RTS=up CTS=up，但是数据仍然不通，说明什么问题？6、 请简单描述at&f命令在modem AT命令集里的作用。