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1、集成电路CAD实训报告系部：尚德光伏学院班级：液晶1001姓名：吴海洋学号：100100266指导老师：陆亚青2012年5月31 / 31文档可自由编辑打印课题一 缓冲器1电路原理图（Schematic Mode 和Symbol Mode）Schematic modeSymbol mode2瞬时分析语句及波形结果3直流分析语句及波形结果.include D:tannerTSpice70modelsml2_125.mdvin IN GND 1.0vvdd Vdd GND 5.0.dc lin source vin 0 5.0 0.02.print dc v(OUT)4版图5LVS对比结果课题二
2、与非门1电路原理图（Schematic Mode 和Symbol Mode）Schematic ModeSymbol Mode2瞬时分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param 1=0.5uvvdd Vdd GND 5.0va A GND PULSE (0 5 50n 5n 5n 100n 200n)vb B GND BIT (0011 lt=50n ht=50n on=5 off=0 rt=5n ft=5n).tran/op 1n 400n method=bdf.print tran v(OUT) v(B) v3直流分析语句
3、及波形结果.include D:tannerTSpice70modelsml2_125.mdva A Gnd 5.0vb B Gnd 5.0vvdd Vdd Gnd 5.0.dc lin source va 0 5.0 0.1 sweep lin source vb 0 5.0 1.print dc v(OUT)4版图5LVS对比结果课题三 或非门1电路原理图（Schematic Mode 和Symbol Mode）Schematic ModeSymbol Mode2瞬时分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param 1=0.5
4、uvvdd Vdd GND 5.0va A GND PULSE (0 5 50n 5n 5n 50n 100n)vb B GND BIT (0011 lt=50n ht=50n on=5 off=0 rt=5n ft=5n).tran/op 1n 400n method=bdf.print tran v(OUT) v(B) v(A)3直流分析语句及波形结果.include D:tannerTSpice70modelsml2_125.mdvvdd Vdd GND 5.0va A GND 5.0vb b GND 5.0.dc lin source va 0 5.0 0.1 sweep lin so
5、urce vb 0 5.0 1.print dc v(OUT)4版图5LVS对比结果课题四 CMOS传输门1电路原理图（Schematic Mode 和Symbol Mode）Schematic ModeSymbol Mode2瞬时分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0vin IN GND PULSE (0 5 50n 5n 5n 50n 100n)vc C GND BIT (1010 lt=50n ht=50n on=5 off=0 rt=5n ft=5n).tran/op
6、 1n 400n method=bdf.print tran v(OUT) v(C) v(IN)3直流分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0vin IN GND 5.0vc C GND 5.0.dc lin source vin 0 5.0 0.1 sweep lin source vc 0 5.0 1.print dc v(OUT)4版图5LVS对比结果课题五 与或非门1电路原理图（Schematic Mode 和Symbol Mode）Schematic ModeSymb
7、ol Mode2瞬时分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0va A GND PULSE (0 5 50n 5n 5n 50n 100n)vb B GND BIT (0011 0110 1010 1100 0111 lt=50n ht=50n on=5 off=0 rt=5n ft=5n)vc C GND PWL (0ns 0V 200ns 0V 205ns 5V 400ns 5V)vd D GND PULSE (5 0 100n 5n 5n 100n 200n).tran/o
8、p 1n 400n method=bdf.print tran v(F) v(D) v(C) v(B) v(A)3直流分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0va A GND 5.0vb B GND 5.0vc C GND 5.0vd D GND 5.0.dc lin source va 0 5.0 1 sweep lin source vb 0 5.0 1 sweep lin source vc 0 5.0 1.print dc v(F)4版图5LVS对比结果课题六 异或门1
9、电路原理图（Schematic Mode 和Symbol Mode）Schematic ModeSymbol Mode2瞬时分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0va A GND PULSE (0 5 50n 5n 5n 50n 100n)vb B GND BIT (0011 1010 0101 lt=50n ht=50n on=5 off=0 rt=5n ft=5n).tran/op 1n 400n method=bdf.print tran v(F) v(B) v(A)3
10、直流分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0va A GND 5.0vb b GND 5.0.dc lin source va 0 5.0 0.1 sweep lin source vb 0 5.0 1.print dc v(F)4版图5LVS对比结果课题七 四位加法器1全加器电路原理图（Schematic Mode 和Symbol Mode）Schematic ModeSymbol Mode2四位加法器电路原理图（Schematic Mode）3四位加法器瞬时分析语句及波形结
11、果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0.vector A A3 A2 A1 A0.vector B B3 B2 B1 B0va A GND BUS (0011 1110 1100 1010 lt=50n ht=50n on=5 off=0 rt=5n ft=5n)vb B GND BUS (1101 0111 1010 0101 lt=50n ht=50n on=5 off=0 rt=5n ft=5n).tran/op 1n 400n method=bdf.print tran v(Cout
12、) v(S3) v(S2) v(S1) v(S0)4四位加法器SPR电路图5四位加法器SPR版图6LVS对比结果课题八 四位减法器1 全减器电路原理图（Schematic Mode 和Symbol Mode）Schematic ModeSymbol Mode2 四位减法器电路原理图（Schematic Mode 和Symbol Mode）Schematic ModeSymbol Mode3四位减法器瞬时分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0.vector A A3 A2 A1
13、 A0.vector B B3 B2 B1 B0va A GND BUS (0011 1110 1100 1010 lt=50n ht=50n on=5 off=0 rt=5n ft=5n)vb B GND BUS (1101 0111 1010 0101 lt=50n ht=50n on=5 off=0 rt=5n ft=5n).tran/op 1n 400n method=bdf.print tran v(Cout) v(S3) v(S2) v(S1) v(S0)4四位减法器SPR电路图5四位减法器SPR版图6LVS对比结果课题九 二选一数据选择器1电路原理图（Schematic Mode
14、 和Symbol Mode）Schematic ModeSymbol Mode2瞬时分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0vd0 D0 GND PULSE (0 5 50n 5n 5n 50n 100n)vd1 D1 GND BIT (1010 lt=50n ht=50n on=5 off=0 rt=5n ft=5n)vs S GND PWL (0ns 0V 200ns 0V 205ns 5V 400ns 5V).tran/op 1n 400n method=bdf.prin
15、t tran v(Y) v(S) v(D1) v(D0)3直流分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0vd0 D0 GND 5.0vd1 D1 GND 5.0vs S GND 5.0.dc lin source vd0 0 5.0 1 sweep lin source vd1 0 5.0 1 sweep lin source vs 0 5.0 1.print dc v(Y)4版图5LVS对比结果课题十 D触发器1电路原理图（Schematic Mode 和Symbol Mode
16、）Schematic ModeSymbol Mode2瞬时分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0vd D GND PULSE (0 5 50n 5n 5n 50n 100n)vclk CLK GND BIT (0101 lt=100n ht=100n on=5 off=0 rt=5n ft=5n).tran/op 1n 400n method=bdf.print tran v(Q) v(CLK) v(D)3直流分析语句及波形结果.include D:tannerTSpice70modelsml2_125.md.param l=0.5uvvdd Vdd GND 5.0vd D GND 5.0vclk CLK GND 5.0.dc lin source vd 0 5.0 0.1 sweep lin source vclk 0 5.0 1.print dc v(Q)4版图5LVS对比结果